What is the complexity of the following code segment (assume all the libraries are included)? int x = 2, n = 10: for(int i=0; i
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A: Ans- WETBLANKET
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A: There is no question in this, Please repost the question with which algorithm we need to decode it.
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A: Hi please find the solution below and I hope it would be helpful for you.
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Q: CIPHERTEXT: SSS RAT BRHENI LYITHG O TY= FIND PLAINTEXT 0
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- Complete the following function definition to recursively print the index of a unique value in an array or -1 if the value is not found:1 int getIndex(int *a, int s, int v) {2 if( ) { // if no values are found3 4 }5 if(a[s-1] == v) { // if a value is found6 7 }8 return getIndex( ); // recurse to check next value9 }Hint:Recurse through the array by counting down from size. 1. Complete the one line of code for line 2:2. Write one line of code for line 3:3. Write one line of code for line 6:4. Complete the one line of code for line 8: please send an atom code. not other softwareinclude<cmath> using namespace std; int main(int argc, char const *argv[]){ int n; cin>>n; // since the divisors occur in pairs, it is enough to traverse till sqrt(n) for(int i=1;i<=sqrt(n);i++) { if(n%i==0) // check the divisibility { if(n/i==i) // if same number appears in the pair, for example for n =100, the number 10 occurs twice. It is enough to print // it once cout<<i<<" "; else // print the divisors cout<<i<<" "<<n/i<<" "; } } // The TC .#include <iostream>using namespace std;void DeleteElement(int *LA,int ITEM,int &N,int K){ for(int j=K;j<=N-1;j++){ LA[j]=LA[j+1]; } N=N-1; }int main(){ int LA[]={1,2,3,4,5,6,7,8}; int N=sizeof(LA)/sizeof(LA[0]); int K=3; int item= LA[K]; DeleteElement(LA,item,N,K); cout<<"Array after deleting value at index K = "<<K<<" is : "<<endl; for(int i=0;i<N;i++){ cout<<LA[i]<<" "; } return 0;}Note: Remove Funcation
- #include double f(double x) { return 4 * exp(-x); } double trapezoidalRule(double a, double b, int N) { double h = (b - a) / N; double sum = 0.5 * (f(a) + f(b)); for (int i = 1; i < N; i++) { sum += f(a + i * h); } return h * sum; } int main() { double a = 0.0; // lower limit double b = 1.0; // upper limit int N = 5; // number of trapezoids double integral = trapezoidalRule(a, b, N); std::cout << "The estimate of the integral of f(x) = 4e^-x between " << a << " and " << b << " using " << N << " trapezoids is: " << integral << std::endl; return 0; } Please write down the explanation, step by step for this trapezoidal rule program, Emphasize on this part:for (int i = 1; i < N; i++) { sum += f(a + i * h); }#include<bits/stdc++.h> using namespace std; void bubbleSort(int arr[], int n) { for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } } } int binarySearch(int arr[], int l, int r, int x, int& comp) { comp++; if (r >= l) { int mid = l + (r - l) / 2; if (arr[mid] == x) { return mid; } if (arr[mid] > x) { return binarySearch(arr, l, mid - 1, x, comp); } return binarySearch(arr, mid + 1, r, x, comp); } return -1; } int main() { int Num[8192]; srand(time(NULL)); for (int i = 0; i < 8192; i++) { Num[i] = rand() % 10001; } clock_t starting_time = clock(); bubbleSort(Num, 8192); clock_t ending_time = clock(); clock_t result =…Code: #include <bits/stdc++.h> using namespace std; void BUBBLE(int A[],int N){ for(int k=0;k<N-1;++k){ for(int ptr=0;ptr<N-k-1;++ptr){ if(A[ptr]>A[ptr+1]){ int temp = A[ptr]; A[ptr] = A[ptr+1]; A[ptr+1]=temp; } } }} //function to print the arrayvoid printArray(int arr[],int n){ int i; for(i=0;i<n;i++) cout<<arr[i]<<" "; cout<<endl;} //driver function to test the modulesint main(){ int arr[] ={15,17,5,3,25,66,14,7,59,100}; int n=sizeof(arr)/sizeof(arr[0]); cout<<"\nOriginal array: "; printArray(arr,n); cout<<"\n\nOutput of Bubble sort are shown below:\n"; BUBBLE(arr,n); printArray(arr, n); return 0;} Q: Remove the Function from the above code
- int getMax(int arr[], int n) { intmx=arr[0]; for (inti=1; i<n; i++) if (arr[i] >mx) mx=arr[i]; returnmx; } Can u give me the code for this one as well....this is the first function and countsort is the secondcorrect this program for generating random number #include<iostream>using namespace std;int *generateRandom(int num);int main(){ int numb; int* number; cout<<"Enter the size of array"; cin>>number; cout<< time(0); number=generateRandom(numb); system("pause"); return 0;}int *generateRandom(int num){ // pointer dynamic array int *array = new int(number); for(int i=0; i<number; i++){ array[i]=rand()%100; } srand(time(0)); cout<<rand();}#include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }
- Remove errors from the program given below. #include<iostream>using namespace std;int main(){ int n; cout<<"Enter size of array : "; cin>>n; char a[n+1]; cout<<"Enter word : "; cin>>a[n+1]; bool check; for(int i=0;i<n;i++){ if(a[i]!=a[n-1-i]){ check = false; break; } else{ check = true; } } check?cout<<"palindrome":cout<<"Not a palindrome"; }Restrict unknown and illogical code. Asking third times. Make sure of correct code./* segvhunt.cFind and eliminate all code that generates Segmentation Fault*/#include <stdio.h>int main() {char **s;char foo[] = "Hello World";*s = foo;printf("s is %s\n",s);s[0] = foo;printf("s[0] is %s\n",s[0]);return(0);}