What is the coefficient in front of the O₂ when the equation below is balanced (using only whole numbers and the lowest whole number ratio)? C2H6O2(g) + O₂ (g) → CO₂(g) + H₂O (g)
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![### Balancing Chemical Equations
**Question:**
What is the coefficient in front of the \( \text{O}_2 \) when the equation below is balanced (using only whole numbers and the lowest whole number ratio)?
**Given Equation:**
\[ \text{C}_2\text{H}_6\text{O}_2(g) + \text{O}_2(g) \rightarrow \text{CO}_2(g) + \text{H}_2\text{O(g)} \]
In order to balance this chemical equation, follow these steps:
1. **Count the number of atoms of each element on both sides of the equation.**
- Left side (Reactants):
- C (Carbon): 2
- H (Hydrogen): 6
- O (Oxygen): 4 (from \( \text{C}_2\text{H}_6\text{O}_2 \)) + 2x (from \( \text{O}_2 \))
- Right side (Products):
- C (Carbon): 1x (from \( \text{CO}_2 \))
- H (Hydrogen): 2y (from \( \text{H}_2\text{O} \))
- O (Oxygen): 2x (from \( \text{CO}_2 \)) + y (from \( \text{H}_2\text{O} \))
2. **Balance the atoms of each element one at a time, using coefficients.**
- Balance Carbon (C):
- Since there are 2 Carbons in the reactants (\( \text{C}_2\text{H}_6\text{O}_2 \)), put a coefficient of 2 in front of \( \text{CO}_2 \).
\[ \text{C}_2\text{H}_6\text{O}_2(g) + \text{O}_2(g) \rightarrow 2 \text{CO}_2(g) + \text{H}_2\text{O(g)} \]
- Balance Hydrogen (H):
- There are 6 Hydrogens in the reactants (\( \text{C}_2\text{H}_6\text{O}_2 \)), so put a coefficient of 3 in front of \( \text{H}_2\](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc3b72c7-eb99-406f-83fe-82fc41b2a8b5%2F9b86f00b-5256-4a0a-9b91-9750a3c11c4c%2Fkuomxas_processed.jpeg&w=3840&q=75)
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