What is the closed form of the following summation? Your solution should be a function in terms of n. For full credit work must be shown. n i ΣΣ i=0 j=0 n i=0 j=0 S 2i+1 -> 1 i=0 i=0 => (2)2' – (n + 1) i=0 n = 2 2' – (n + 1) i=0 = 2(2n+1 – 1) – (n + 1) = 2n+2 – 2 - n - 1 = 2n+2 – n – 3 %3D -
What is the closed form of the following summation? Your solution should be a function in terms of n. For full credit work must be shown. n i ΣΣ i=0 j=0 n i=0 j=0 S 2i+1 -> 1 i=0 i=0 => (2)2' – (n + 1) i=0 n = 2 2' – (n + 1) i=0 = 2(2n+1 – 1) – (n + 1) = 2n+2 – 2 - n - 1 = 2n+2 – n – 3 %3D -
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![What is the closed form of the following summation? Your solution should be a function in terms of n.
For full credit work must be shown.
n i
ΣΣ
i=0 j=0
EE2 = Ec2*1 – 1)
i=0 j=0
i=0
n
> 2i+1 ->1
i=0
i=0
=>
(2)2 – (n+ 1)
i=0
= 2 ) 2' – (n + 1)
i=0
= 2(2"+1 – 1) – (n + 1)
= 2n+2 – 2 – n – 1
= 2n+2 – n – 3
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d4fd4d4-77c7-4e93-950b-25099f54e660%2Fc473f7ba-1714-4284-aa59-2eab34a34770%2F2lm2sok_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What is the closed form of the following summation? Your solution should be a function in terms of n.
For full credit work must be shown.
n i
ΣΣ
i=0 j=0
EE2 = Ec2*1 – 1)
i=0 j=0
i=0
n
> 2i+1 ->1
i=0
i=0
=>
(2)2 – (n+ 1)
i=0
= 2 ) 2' – (n + 1)
i=0
= 2(2"+1 – 1) – (n + 1)
= 2n+2 – 2 – n – 1
= 2n+2 – n – 3
-
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