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What is the change of energy (L. atm) of a system that absorbed 19.9 L.atm of heat and had its volume changed from 5.6 L to 11.2 L against a pressure of 1.5 atm? AE = -19.9 + [-1.5(11.2 - 5.6)] %3D AE = 19.9 + [1.5(11.2 + 5.6)] %3D AE = 19.9 +[- 1.5(11.2 - 5.6)] %3D AE = -19.9 + [1.5(11.2 - 5.6)]

What is the change of energy (L. atm) of a system that absorbed 19.9 L.atm of heat and had its volume changed from 5.6 L to 11.2 L against a pressure of 1.5 atm? AE = -19.9 + [-1.5(11.2 - 5.6)] %3D AE = 19.9 + [1.5(11.2 + 5.6)] %3D AE = 19.9 +[- 1.5(11.2 - 5.6)] %3D AE = -19.9 + [1.5(11.2 - 5.6)]

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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What is the change of energy (L. atm) of a system that absorbed 19.9 L.atm of heat and had its volume changed from 5.6 L to 11.2 L against a pressure of 1.5 atm? AE = -19.9 + [-1.5(11.2 - 5.6)] %3D ДЕ - 19.9 + [1.5(11.2 + 5.6)] Ο ΔΕ 19.9 +[- 1.5(11.2 - 5.6)] AE = -19.9 + [1.5(11.2 - 5.6)]
Transcribed Image Text:What is the change of energy (L. atm) of a system that absorbed 19.9 L.atm of heat and had its volume changed from 5.6 L to 11.2 L against a pressure of 1.5 atm? AE = -19.9 + [-1.5(11.2 - 5.6)] %3D ДЕ - 19.9 + [1.5(11.2 + 5.6)] Ο ΔΕ 19.9 +[- 1.5(11.2 - 5.6)] AE = -19.9 + [1.5(11.2 - 5.6)]
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