.COAktiv ChemistryWhat is the change in enthalpy when 1.25 moles of O₂ are reacted with an excess H₂of according to the following balanced chemical reaction:2 H₂(g) + O₂(g) → 2 H₂O(l)ΔΗ = -572 kJ-572mol H₂ADD FACTORx ( )458g 0₂1kJQuestion 19 of 207152g H₂O1.25ANSWER18.02mol O₂DELL-4582.02mol H₂ORESETJ2-71532.0g H₂TEL

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What is the change in enthalpy when 1.25 moles of O₂ are reacted with an excess H₂ of according to the following balanced chemical reaction: 2 H₂(g) + O₂(g) → 2 H₂O(1) ΔΗ = -572 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.

Question

.CO
Aktiv Chemistry
What is the change in enthalpy when 1.25 moles of O₂ are reacted with an excess H₂
of according to the following balanced chemical reaction:
2 H₂(g) + O₂(g) → 2 H₂O(l)
ΔΗ = -572 kJ
-572
mol H₂
ADD FACTOR
x ( )
458
g 0₂
1
kJ
Question 19 of 20
715
2
g H₂O
1.25
ANSWER
18.02
mol O₂
DELL
-458
2.02
mol H₂O
RESET
J
2
-715
32.0
g H₂
TEL

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