What is the change in enthalpy when 1.25 moles 0₂ are reacted with an excess H₂ of according to the following balanced chemical reaction: 2 H₂(g) + O₂(g) → ΔΗ = -572 kJ STARTING AMOUNT 2 H₂O(l) X
What is the change in enthalpy when 1.25 moles 0₂ are reacted with an excess H₂ of according to the following balanced chemical reaction: 2 H₂(g) + O₂(g) → ΔΗ = -572 kJ STARTING AMOUNT 2 H₂O(l) X
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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6:43
What is the change in enthalpy when 1.25
moles of O2
are reacted with an excess H₂ of according to the following
balanced chemical reaction:
ADD FACTOR
x( )
STARTING AMOUNT
-572
458
1
2
18.02
2.02
-715
2
32.0
H₂(g) + O₂(g) → 2
Question 8 of 25
ΔΗ = -572
715
1.25
-458
X
kJ
ANSWER
mol H₂
g 0₂
kJ
g H₂O
mol O₂
J
mol H₂O
g H₂
Tap here or pull up for additional resources
Submit
H₂O (1)
RESET
3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8239f6e0-33cd-4a60-b81c-7954cdd0e0a0%2F60f4592a-2e5b-4873-9379-56f637cff58a%2Flikcwvg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:<
6:43
What is the change in enthalpy when 1.25
moles of O2
are reacted with an excess H₂ of according to the following
balanced chemical reaction:
ADD FACTOR
x( )
STARTING AMOUNT
-572
458
1
2
18.02
2.02
-715
2
32.0
H₂(g) + O₂(g) → 2
Question 8 of 25
ΔΗ = -572
715
1.25
-458
X
kJ
ANSWER
mol H₂
g 0₂
kJ
g H₂O
mol O₂
J
mol H₂O
g H₂
Tap here or pull up for additional resources
Submit
H₂O (1)
RESET
3
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