What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cu+ concentration is 1.16 M and the Znt concentration is 3.83 x 10 M? Cu* (aq) + Zn(s) → Cu(s) + Zn+ (aq) Ecell V The cell reaction as written above is v for the concentrations given. spontaneous nonspontaneous Submit Answer Retry Entire Group pts remaining

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The Nernst Equation
A nonstandard cell or half-cell potential can be calculated using the Nernst equation:
RT
E = E° -
InQ
nF
where
E = potential under nonstandard conditions
E = standard potential
R = ideal gas constant = 8.314 J/K mol
%3D
%3D
T = kelvin temperature
number of moles of electrons for the reaction as
written
F = charge carried by 1 mol of electrons =
96, 485 C/mol = 96, 485 J/V · mol
%3D
= reaction quotient
%3D
It is customary to use the equation in a form where numberical values are substituted for R, T, and F at a temperature of 25° C.
(8.314 J/K - mol)(298K)
96, 485 J/V mol
RT
= 0.02568 V
F
and the Nernst equation with the potentials in volts is:
E = E° –
0.02568
In Q
Sometimes it is more convenient to use base-10 logarithms, and the substitution of 2.3026 log for In is made.
(2.3026 x 0.02568 = 0.0591)
%3D
E = E
0.0591
logQ
–
A common student error is to use the wrong kind of logarithm. Be sure, when you choose an equation, to use the correct
logarithm.
=- EEUEU Tor this question.
What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cu+
concentration is 1.16 M and the Zn concentration is 3.83 x 10¬ M ?
Cu?+ (aq) + Zn(s) → Cu(s) + Zn²+ (aq)
Ecell
V
The cell reaction as written above is
for the concentrations given.
spontaneous
Submit Answer
Retry Entire Group
nonspontaneous
pts remaining
Transcribed Image Text:The Nernst Equation A nonstandard cell or half-cell potential can be calculated using the Nernst equation: RT E = E° - InQ nF where E = potential under nonstandard conditions E = standard potential R = ideal gas constant = 8.314 J/K mol %3D %3D T = kelvin temperature number of moles of electrons for the reaction as written F = charge carried by 1 mol of electrons = 96, 485 C/mol = 96, 485 J/V · mol %3D = reaction quotient %3D It is customary to use the equation in a form where numberical values are substituted for R, T, and F at a temperature of 25° C. (8.314 J/K - mol)(298K) 96, 485 J/V mol RT = 0.02568 V F and the Nernst equation with the potentials in volts is: E = E° – 0.02568 In Q Sometimes it is more convenient to use base-10 logarithms, and the substitution of 2.3026 log for In is made. (2.3026 x 0.02568 = 0.0591) %3D E = E 0.0591 logQ – A common student error is to use the wrong kind of logarithm. Be sure, when you choose an equation, to use the correct logarithm. =- EEUEU Tor this question. What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cu+ concentration is 1.16 M and the Zn concentration is 3.83 x 10¬ M ? Cu?+ (aq) + Zn(s) → Cu(s) + Zn²+ (aq) Ecell V The cell reaction as written above is for the concentrations given. spontaneous Submit Answer Retry Entire Group nonspontaneous pts remaining
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