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What is the binding energy in kJ/mol La for lanthanum-138? 8.1x10^8 x kJ/mol 57 H+ 81,n-7La The required masses (g/mol) are: H= 1.00783 ;;n= 1.00867 ; 0 138 138

What is the binding energy in kJ/mol La for lanthanum-138? 8.1x10^8 x kJ/mol 57 H+ 81,n-7La The required masses (g/mol) are: H= 1.00783 ;;n= 1.00867 ; 0 138 138

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What is the binding energy in kJ/mol La for lanthanum-138? 8.1x10^8 x kJ/mol 57 H+ 81,n- 138 57La The required masses (g/mol) are:H= 1.00783 ;'n= 1.00867 ; 138 La = 137.90680 57
Transcribed Image Text:What is the binding energy in kJ/mol La for lanthanum-138? 8.1x10^8 x kJ/mol 57 H+ 81,n- 138 57La The required masses (g/mol) are:H= 1.00783 ;'n= 1.00867 ; 138 La = 137.90680 57
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explain to me why your answer is wrong and the answer is somewhat like this pls explain i don't understand

The mass of the nucleus of an atom is less than that which would be predicted by summing the masses of the constituent nucleons. The energy equivalent of this mass deficit is called the binding energy. This is the equivalent of calculating AE for the exothermic process: 57 H+ 81;n→ La where the binding energy, Eb, is the negative of AE. (1) First calculate the difference between the atomic mass and the sum of the masses of the individual nucleons: The number of protons = atomic number = 57 The mass number for lanthanum-138 = 138 The number of neutrons = mass number - atomic number = 138 - 57 = 81 The atomic mass of La = 137.90680 The proton mass = 1.00783 The neutron mass = 1.00867 Mass deficit = 137.90680 - [ 57(1.00783) + 81(1.00867) ] = -1.24178 g/mol = -1.24178×10-3 kg/mol (2) Now calculate the energy equivalent of the mass deficit: E = mc2 (units: J = kg m²/s²) 3.00x108 m 2 1 k) 1.12×1011 k) Eb= -(-1.24178×10-3) kg x 1000 J mol 138 La
Transcribed Image Text:The mass of the nucleus of an atom is less than that which would be predicted by summing the masses of the constituent nucleons. The energy equivalent of this mass deficit is called the binding energy. This is the equivalent of calculating AE for the exothermic process: 57 H+ 81;n→ La where the binding energy, Eb, is the negative of AE. (1) First calculate the difference between the atomic mass and the sum of the masses of the individual nucleons: The number of protons = atomic number = 57 The mass number for lanthanum-138 = 138 The number of neutrons = mass number - atomic number = 138 - 57 = 81 The atomic mass of La = 137.90680 The proton mass = 1.00783 The neutron mass = 1.00867 Mass deficit = 137.90680 - [ 57(1.00783) + 81(1.00867) ] = -1.24178 g/mol = -1.24178×10-3 kg/mol (2) Now calculate the energy equivalent of the mass deficit: E = mc2 (units: J = kg m²/s²) 3.00x108 m 2 1 k) 1.12×1011 k) Eb= -(-1.24178×10-3) kg x 1000 J mol 138 La
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