What is the Big Theta runtime of this function, where n is the length of the list? def f(1st): i = 1 while i < len(1st): j = i + 1 while j / 2 > i: 1st[j] j = j + 1 i + 1 i+j %3D %3D
What is the Big Theta runtime of this function, where n is the length of the list? def f(1st): i = 1 while i < len(1st): j = i + 1 while j / 2 > i: 1st[j] j = j + 1 i + 1 i+j %3D %3D
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:Theta(log n)
Theta(n)
Theta(n log n)
Theta(n^2)
This code does not terminate.
This code does not have a tight Theta bound.
![What is the Big Theta runtime of this function, where n is the length of the list?
def f(1st):
i = 1
while i < len(1st):
j
i + 1
while j / 2 > i:
1st[j]
j = j + 1
i = i + 1
%3D
i+j](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F951c6e99-c785-4ffc-a421-a2fa6db17aa1%2Fed4e21ae-0a07-4571-bff8-d2bb9ff3bdff%2Fpmh8eo_processed.png&w=3840&q=75)
Transcribed Image Text:What is the Big Theta runtime of this function, where n is the length of the list?
def f(1st):
i = 1
while i < len(1st):
j
i + 1
while j / 2 > i:
1st[j]
j = j + 1
i = i + 1
%3D
i+j
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