### Finding the Area of a Triangle on a Coordinate Plane**Problem:**What is the area of the triangle with vertices \( L(-3, 5) \), \( M(4, 7) \), and \( N(2, -8) \)? Use any method to find the answer.**Graph Description:**The graph provided shows a coordinate plane with a triangle outlined. The vertices of the triangle are marked as follows:- \( L \) at coordinates \((-3, 5)\)- \( M \) at coordinates \((4, 7)\)- \( N \) at coordinates \((2, -8)\)The x-axis and y-axis intersect at the origin \((0, 0)\). The grid lines are labeled incrementally with numbers, both positive and negative.**Options:**- 25.5 square units.- 57.5 square units.- 45.5 square units.- 50.5 square units.**Method:**To find the area of a triangle given its vertices, you can use the formula:\[\text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|\]Substitute the coordinates of \( L(-3, 5) \), \( M(4, 7) \), and \( N(2, -8) \):- \( x_1 = -3 \), \( y_1 = 5 \)- \( x_2 = 4 \), \( y_2 = 7 \)- \( x_3 = 2 \), \( y_3 = -8 \)Calculate the area:\[\begin{align*}\text{Area} &= \frac{1}{2} \left| (-3)(7 - (-8)) + 4((-8) - 5) + 2(5 - 7) \right| \\&= \frac{1}{2} \left| (-3)(15) + 4(-13) + 2(-2) \right| \\&= \frac{1}{2} \left| (-45) + (-52) + (-4) \right| \\&

Name: ### Finding the Area of a Triangle on a Coordinate Plane**Problem:**W
Uploaded: 2024-03-20T06:47:08.000Z
Channel: Bartleby
Description: ### Finding the Area of a Triangle on a Coordinate Plane**Problem:**What is the area of the triangle with vertices \( L(-3, 5) \), \( M(4, 7) \), and \( N(2, -8) \)? Use any method to find the answer.**Graph Description:**The graph provided shows a