What is the area of a rectangle whose electric flux is 43 C^2/Nm^2 and electric field of 84nN/C
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Q: The following charges are located inside a submarine:5.00 µC, -9.00 pc, 27.0 pc, and -84.0 pc.…
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A: length of side = d = 9 mcharge = q = 8.016 x 10-6 C
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Q: uniform electric field of magnitude E=435 N/C makes an angle of θ= 65.0 ° with a plane surface of…
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What is the area of a rectangle whose electric flux is 43 C^2/Nm^2 and electric field of 84nN/C
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- A sphere surrounds three charged particles of charges q1 = 4.16×10-10 C, q2 = 9.06×10-11 C, and q3 = 5.74×10-10 C. Use Gauss's Law to determine the total electric flux (Φ) passing through the surface. Your answer should be in N·m2/C.The electric flux through the surface shown in the figure is 17 Nm^2/C. What is the electric field strength? Express your answer to two significant figures and include the appropriate unitsA circular surface with a radius of 0.066 m is exposed to a uniform electric field of magnitude 1.90 × 104 N/C. The electric flux through the surface is 52 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?
- A uniformly charged ring of radius 10.0 cm has a total charge of 56.0 ?C. Find the electric field on the axis of the ring at the following distances from the center of the ring. (Choose the x-axis to point along the axis of the ring.) 1.00 cm _________ î MN/C 5.00 cm _________ î MN/C 30.00 cm _________ î MN/C 100.00 cm _________ î MN/Ca circular surface with a radius of 0.061 m is exposed to a uniform electric field of magnitude 1.88E4 N/C. The electric flux through the surface is 77 Nm^2/C. What is the angle between the diraction of the electric field and the normal to the surfaceAt a distance of 7.50 x 10-1 m from a small charged object the electric field strength is 2.10 x 104 N/C. At what distance from this same object would the electric field strength be 4.20 x 104 N/C?
- A circular surface with a radius of 0.062 m is exposed to a uniform electric field of magnitude 1.58 × 104 N/C. The electric flux through the surface is 68 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?The figure below shows a uniform electric field of magnitude E = 420 N/C making an angle of o = 66.5° with a flat surface of area A = 3.20 m2. What is the magnitude of the electric flux through this surface (in N · m2/C)? E N. m2/cA hollow spherical shell with a diameter of 3.8 cm has a charge of 1.91 n C placed at its center. Calculate the electric flux through a portion of the shell with an area of 1.40 X 10-2 m2 zero 80 Nm^2/C 56 2 Nm^2/C 215.8 Nm^2/C
- Find the flux in N.m².C-1 of a constant electric field E = (5.3180x10^3) i + (-5.514x10^3)j + (-1.5880x10^3) k N/C, passing through an area defined by the area vector A = (-4.7990x10^0) i + (-7.69x10^0) j + (4.2900x10^-1) k m².The following charges are located inside a submarine: 7.80 µC, −9.00 µC, 27.0 µC, and −58 µC. (a) Calculate the net electric flux through the hull of the submarine. N · m2/CA vertical wall (6.3 mx 3.3 m) in a house faces due east. A uniform electric field has a magnitude of 210 N/C. This field is parallel to the ground and points 34° north of east. What is the electric flux through the wall? Number: Units