In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of theC-H is in the direction ofA = î + Î +Rand an adjacent C-H bond is at the directionB=î-7-R.results to an angular bond of approximately 109° for a static frozen molecule.However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to varyslightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to beA = 1.07i + 0.83j + 0.81kB = 1.03i + -0.99j + -0.85kWhat is the angle (in degrees) between the bonds based on this new data?Note: Only 1% of error is permitted for the correct answer.

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Answered: What is the angle (in degrees) between…

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter42: Molecules And Solids

Section: Chapter Questions

Problem 13P

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A carbon nanotube is a nanometer-scale cylindrical tube composed of carbon atoms. One of its interesting properties is a very large Youngs modulus, measured to be more than 1.000 1012 N/m2. A tensile stress of 5.3 1010 N/m2 is exerted on a particular nanotube with a Youngs modulus measured at 2.130 1012 N/m2. Assuming the nanotube obeys Hookes law, by what percentage does the atomic spacing increase?
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= i-hat + j-hat + k-hat and an adjacent C-H bond is at the direction B= i-hat - j-hat - k-hat results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.96i + 0.87j + 0.8k B = 0.94i + -0.98j + -1.07k What is the angle (in degrees) between the bonds based on this new data?
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k
In solid KCI the smallest distance between the centers of a. potassium ion and a chloride ion is 314 pm. Calculate the length of the edge of the unit cell and the density of KCI, assuming it has the same structure as sodium chloride.
Discuss the differences between the rotational and vibrational energy levels of the deuterium (“heavy hydrogen”) molecule D2 and those of the ordinary hydrogen molecule H2. A deuterium atom has twice the mass of an ordinary hydrogen atom.
p9C.1 Familiarity with the magnitudes of overlap integrals is useful when con- sidering bonding abilities of atoms, and hydrogenic orbitals give an indication of their values. (a) The overlap integral between two hydrogenic 2s orbitals is 1 ( ZR ZR +. 2а, " 12 а, 1 + ZR 240 a, -ZR/Z0 S(2s, 2s)={1+ Plot this expression. (b) For what internuclear distance is S(2s,2s) = 0.50? (c) The side-by-side overlap of two 2p orbitals of atoms of atomic number Z is ZR 1 ( ZR ZR S(2p,2p) ={1+ 10 a, 2a, 120 a. Plot this expression. (d) Evaluate S(2s,2p) at the internuclear distance you calculated in part (b).
A diatomic molecule has 18 x 105 eV of rotational energy in the I = 7 quantum state. What is its rotational energy in the I = 0 quantum state? %3D
Molecular Pair Potential The vibrational properties of a diatomic molecule can often be described by Mie's pair potential 3: U(r) = C c[9₁-9] (4) where U(r) is the potential energy between the two atoms, r is the distance between the two atoms, C, o are positive constants, and λ > 6 is a constant. The case with X 12 is the Lennard-Jones potential and was covered in Lecture #2. For the purposes of this problem, assume there is a mass ‘m’ that represents the dynamical mass of the molecule. 4 TLTR: (a) Find a combination of C, m, o that has the units of frequency. (b) Derive the ratio of the equilibrium positions and of the frequencies of small oscillations for X 10, 14. Show that the units for the equilibrium position and for the frequency of the oscillations are consistent.
Obtain the expression for the rotational kinetic energy of the molecule.
The displacement distance of an atom around a dislocation (line defect in a crystal or grains) is called the slip or Burgers vector b and is (a)/(b) to an edge dislocation line. The slip or Burgers vector of a screw dislocation is (c)/(d) to the dislocation line. Choose either (a) or (b) and (c) or (d) to correctly finish the sentence. A. (b) perpendicular/ loodreg B. (d) perpendicular/ loodreg C. (a) parallel D. (c) parallel
(a) Express the moment of inertia of an octahedral AB6 molecule in terms of its bond lengths and the masses of the B atoms. (b) Ca lcu late the rotationa l constant of 32S19F6, for which the S-F bond length is 158 pm.
A water molecule consists of an oxygen atomwith two hydrogen atoms bound to it. Theangle between the two bonds is 106◦ If each bond is 0.128 nm long, how far fromthe oxygen atom is the center of mass of themolecule? Take the mass of an oxygen atomto be 16 times the mass of a hydrogen atom.Answer in units of nm.

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