Question 8What is the air to fuel ratio AF (mass basis) of the complete combustion of propane?C3Hg + 5 (02 + 3.76 N2) -> 3 CO2 + 4 H20 + 18.8 N2Take:M(C3Hg)= 44.1 g/molM(air) = 28.91 g/mol%3D7.63 kg(air)/kg(fuel)a.b. 36.31 kg(air)/kg(fuel)3.28 kg(air)/kg(fuel)C.15.6 kg(air)/kg(fuel)d.Moving to the next question prevents changes to this answer.

Answered: Image /qna-images/answer/292dd34f-b845-4414-ba05-71b26032d37c.jpg

What is the air to fuel ratio AF (mass basis) of the complete combustion of propane? C3H8 + 5 (02 + 3.76 N2) -> 3 CO2 + 4 H20 + 18.8 N2 Take: M(C3Ha) = 44.1 g/mol M(air) = 28.91 g/mol a. 7.63 kg(air)/kg(fuel) Ob. 36.31 kg(air)/kg(fuel) 3.28 kg(air)/kg(fuel) C. d. 15.6 kg(air)/kg(fuel)

What is the air to fuel ratio AF (mass basis) of the complete combustion of propane? C3H8 + 5 (02 + 3.76 N2) -> 3 CO2 + 4 H20 + 18.8 N2 Take: M(C3Ha) = 44.1 g/mol M(air) = 28.91 g/mol a. 7.63 kg(air)/kg(fuel) Ob. 36.31 kg(air)/kg(fuel) 3.28 kg(air)/kg(fuel) C. d. 15.6 kg(air)/kg(fuel)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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