What is the actual volumetric flow rate in ft2/sec for the discharge of a tank through a 0.5 ft? orifice under a head of 8 ft water, if the coefficient of contraction for the orifice is 0.61 and the coefficient of velocity is 0.98?
What is the actual volumetric flow rate in ft2/sec for the discharge of a tank through a 0.5 ft? orifice under a head of 8 ft water, if the coefficient of contraction for the orifice is 0.61 and the coefficient of velocity is 0.98?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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INSTRUCTIONS: Solve theproblems neatly and systematically. Use free-floating decimals in all your calculations and in expressing your answers. Box your final answers
KINDLY FOLLOW THIS FORMAT GIVE,REQUIRED,SOLUTION
ADDITIONAL: USE THE OTHER PICTURE AS BASIS FORMULA IF NEEDED IN YOUR SOLUTION THANK YOU
Transcribed Image Text:6) What is the actual volumetric flow rate in ft?/sec for the discharge of a tank through a 0.5 ft?
orifice under a head of 8 ft water, if the coefficient of contraction for the orifice is 0.61 and the
coefficient of velocity is 0.98?
Transcribed Image Text:DEVELOPED HEAD:
Bernoulli Equation:
(P2, azV?
+
2gc
a,V?
+ 21°
2gc
Притр Wpитр
+ z2
P2
gc
The quantities in parenthesis are called TOTAL HEADS and are denoted by H.
Therefore: Wp
Нь-На
AH
POWER REQUIREMENT:
PB = m Wp = m AH
Pr
%3D
EDIFICA
where:
Pa, Po = pressure at the suction and discharge lines
V = velocity
H = total head
Ps = the power supplied to the pump
Z = height above the datum plane
P: = the power delivered to the fluid
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