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WHAT IS THE 6 T 4'-6" 45° 6'2". 7'2" A₁ VOLUME OF ZEKE'S DUMP TRUCK BED? FEET A₁ = 7'2" x 5¹ = (7+²/12) (5) = 35.83 ft ² V₁ = (35.83 ++²) (19¹) = 680.83 ft ³ A₂ = ½ bh = V₂ = 1½1⁄2 (0.5') (0.5') = 0,125 ft² (0.125 ft²) (19¹) = 2.375 ft ³ V TOTAL = V₁ V₂ - V₂ = 680.23 ft³ - 2.375 ft³ - 2.375 ft³

WHAT IS THE 6 T 4'-6" 45° 6'2". 7'2" A₁ VOLUME OF ZEKE'S DUMP TRUCK BED? FEET A₁ = 7'2" x 5¹ = (7+²/12) (5) = 35.83 ft ² V₁ = (35.83 ++²) (19¹) = 680.83 ft ³ A₂ = ½ bh = V₂ = 1½1⁄2 (0.5') (0.5') = 0,125 ft² (0.125 ft²) (19¹) = 2.375 ft ³ V TOTAL = V₁ V₂ - V₂ = 680.23 ft³ - 2.375 ft³ - 2.375 ft³

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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WHAT IS THE VOLUME OF ZEKE'S DUMP TRUCK BED? T 4'-6" # ۲/ —7'2" 450 76'2" 4 7'2" A₁ IN FEET A₁ = 7'2" x 5' = (7 + ²/2) (5) = 35.83 ft² V₁ = (35.83 ++²) (19') = 680.83 ft ³ A₂ = 1/2 bh = 1½1⁄2 (0.5') (0.5') = 0,125 ft² V₂ = (0,125 ft²) (19¹) = 2.375 ft ³ V TOTAL = V₁ - V₂ - V₂ = (1 680.23 ft³ - 2.375 ft³ - 2.375 ft ³
Transcribed Image Text:WHAT IS THE VOLUME OF ZEKE'S DUMP TRUCK BED? T 4'-6" # ۲/ —7'2" 450 76'2" 4 7'2" A₁ IN FEET A₁ = 7'2" x 5' = (7 + ²/2) (5) = 35.83 ft² V₁ = (35.83 ++²) (19') = 680.83 ft ³ A₂ = 1/2 bh = 1½1⁄2 (0.5') (0.5') = 0,125 ft² V₂ = (0,125 ft²) (19¹) = 2.375 ft ³ V TOTAL = V₁ - V₂ - V₂ = (1 680.23 ft³ - 2.375 ft³ - 2.375 ft ³
Expert Solution
Step 1: Given information

Given a diagram of the bed of a dump truck and its measurements.

To find the volume of the dump truck.


For a right angled triangle increment A B C right angled at B,

tan space A equals fraction numerator B C over denominator A B end fraction equals perpendicular over base .

The area of  a right angled triangle is 

A equals 1 half cross times base cross times perpendicular .


One feet equals 12 inches, 

i.e., 1 apostrophe equals 12 apostrophe apostrophe .

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