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What is printed for the call myPrint (10)?

What is printed for the call myPrint (10)?

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Below is the transcription of the code sample and associated problem from the image: --- ### Recursive Method Example: `myPrint` Consider the recursive method `myPrint`: ```java public void myPrint(int n) { if (n < 10) { System.out.print(n); } else { int m = n % 10; System.out.print(m); myPrint(n / 10); } } ``` **Question:** What is printed for the call `myPrint(10)`? --- ### Explanation **Code Details:** - This code defines a recursive method `myPrint` which takes an integer `n` as a parameter. - If `n` is less than 10, it prints `n`. - If `n` is 10 or greater: - It calculates `m` as the remainder of `n` divided by 10 (`n % 10`). - It prints `m`. - It then recursively calls `myPrint` with the integer division of `n` by 10 (`n / 10`). **Execution of `myPrint(10)`**: 1. `n = 10`, which is not less than 10, so the else block executes. 2. `m = 10 % 10 = 0`, then `0` is printed. 3. The method `myPrint(10 / 10)` is called, i.e., `myPrint(1)`. 4. Now, `n = 1`, which is less than 10, so `1` is printed. **Output:** For `myPrint(10)`, the printed output is `01`.
Transcribed Image Text:Below is the transcription of the code sample and associated problem from the image: --- ### Recursive Method Example: `myPrint` Consider the recursive method `myPrint`: ```java public void myPrint(int n) { if (n < 10) { System.out.print(n); } else { int m = n % 10; System.out.print(m); myPrint(n / 10); } } ``` **Question:** What is printed for the call `myPrint(10)`? --- ### Explanation **Code Details:** - This code defines a recursive method `myPrint` which takes an integer `n` as a parameter. - If `n` is less than 10, it prints `n`. - If `n` is 10 or greater: - It calculates `m` as the remainder of `n` divided by 10 (`n % 10`). - It prints `m`. - It then recursively calls `myPrint` with the integer division of `n` by 10 (`n / 10`). **Execution of `myPrint(10)`**: 1. `n = 10`, which is not less than 10, so the else block executes. 2. `m = 10 % 10 = 0`, then `0` is printed. 3. The method `myPrint(10 / 10)` is called, i.e., `myPrint(1)`. 4. Now, `n = 1`, which is less than 10, so `1` is printed. **Output:** For `myPrint(10)`, the printed output is `01`.
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