What is output? import java.util.ArrayList; public class SimpleCar { @Override public String toString(){ return "I drive fast";

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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### Question 16

**What is output?**

```java
import java.util.ArrayList;

public class SimpleCar {
    @Override
    public String toString(){
        return "I drive fast";
    }

    public static void main(String[] args){
        ArrayList<Object> myStuff;
        myStuff = new ArrayList<Object>();
        myStuff.add(new String("Greetings"));
        myStuff.add(new Object());
        myStuff.add(new SimpleCar());
        for(Object item : myStuff){
            System.out.println(item.toString());
        }
    }
}
```

#### Multiple Choice Answers:

- **[ ] String Object SimpleCar**
- **[ ] java.lang.Object@19cc java.lang.Object@23fb java.lang.Object@ab79**
- **[O] java.lang.String@169b java.lang.Object@23fb java.lang.SimpleCar@a42b**
- **[ ] Greetings java.lang.Object@169b I drive fast**

### Explanation

This Java code involves an `ArrayList` of `Object` type, which is populated with various objects, including a `String`, a generic `Object`, and an instance of the `SimpleCar` class. When the program runs, it:

1. Overrides the `toString()` method of the `SimpleCar` class to return "I drive fast".
2. Adds a `String`, an `Object`, and a `SimpleCar` instance to the `ArrayList`.
3. Iterates over the list and prints the `toString()` value of each item.

The correct output will display the default `toString()` values for the `String` and `Object` classes, and the overridden `toString()` for the `SimpleCar` class:

- The `String` object will print `java.lang.String@169b`.
- The `Object` will print `java.lang.Object@23fb`.
- The `SimpleCar` will print `java.lang.SimpleCar@a42b`.
Transcribed Image Text:### Question 16 **What is output?** ```java import java.util.ArrayList; public class SimpleCar { @Override public String toString(){ return "I drive fast"; } public static void main(String[] args){ ArrayList<Object> myStuff; myStuff = new ArrayList<Object>(); myStuff.add(new String("Greetings")); myStuff.add(new Object()); myStuff.add(new SimpleCar()); for(Object item : myStuff){ System.out.println(item.toString()); } } } ``` #### Multiple Choice Answers: - **[ ] String Object SimpleCar** - **[ ] java.lang.Object@19cc java.lang.Object@23fb java.lang.Object@ab79** - **[O] java.lang.String@169b java.lang.Object@23fb java.lang.SimpleCar@a42b** - **[ ] Greetings java.lang.Object@169b I drive fast** ### Explanation This Java code involves an `ArrayList` of `Object` type, which is populated with various objects, including a `String`, a generic `Object`, and an instance of the `SimpleCar` class. When the program runs, it: 1. Overrides the `toString()` method of the `SimpleCar` class to return "I drive fast". 2. Adds a `String`, an `Object`, and a `SimpleCar` instance to the `ArrayList`. 3. Iterates over the list and prints the `toString()` value of each item. The correct output will display the default `toString()` values for the `String` and `Object` classes, and the overridden `toString()` for the `SimpleCar` class: - The `String` object will print `java.lang.String@169b`. - The `Object` will print `java.lang.Object@23fb`. - The `SimpleCar` will print `java.lang.SimpleCar@a42b`.
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