What is equation of the line normal to graph of y = x^3 + 3x^2 + 7x - 1 at the point where x = -1? O 4x + y + 10 = 0 O x - 4y - 23 = 0 4x - y - 2 = 0 x + 4y + 25 = 0

Q: Find the point of inflection of the curve y = x^3 - 6x^2 - x + 12. (-2,6) (2,-6) (-2,-6) (2,6)

A: We have to find point of inflection of given function.

Q: X^4+y^2=3 find the slope of the function above at (1,-sqrt2)

A: Explanation of the solution is given below....

Q: how I sketch the graph for  y=x^2+4x+3?

A: Given: The function, y = x2 + 4x + 3

Q: the x intercept of the equation y=x^2-9x+20 are m and n where m>n. what is the value of m

A: Given equation is y=x2-9x+20To find x intercept we must equate for y=0Therefore,y= x2-9x+20