What happens when the loop encloses no current?What happens when the loop encloses both positive (out of the screen) and negative (into the screen) currentThe four sides of the path contribute different amounts to the total integral. Under which circumstances will the contribution from a side be zero?The magnetic field within a solenoid is uniform. By playing around with this simulation, can you explain why that must be the case? p00000000000odo000obo00000000000000000003B = 18.85 mT00001 mmPath 1:Path 2:[8. di = 0 mT - mm[6 . ds = 5.84 mT mmTurns/Length :Path 3:Path 4:n = 5 mm-B. ds = 25.32 mT - mmds = -10.05 mT · mmCurrent :Complete Path :lenc = 16.81 A|= 3 AB - ds = 21.12 mT - mmHo lene = 21.12 mT. mm

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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What happens when the loop encloses no current?
What happens when the loop encloses both positive (out of the screen) and negative (into the screen) current
The four sides of the path contribute different amounts to the total integral. Under which circumstances will the contribution from a side be zero?
The magnetic field within a solenoid is uniform. By playing around with this simulation, can you explain why that must be the case?

p00000000000odo000obo0000000000000000000
3
B = 18.85 mT
0000
1 mm
Path 1:
Path 2:
[8. di = 0 mT - mm
[6 . ds = 5.84 mT mm
Turns/Length :
Path 3:
Path 4:
n = 5 mm-
B. ds = 25.32 mT - mm
ds = -10.05 mT · mm
Current :
Complete Path :
lenc = 16.81 A
|= 3 A
B - ds = 21.12 mT - mm
Ho lene = 21.12 mT. mm

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