What happens when SW2 is closed? O The potential at the junction between R1 and R3 is pulled high, causing a potential difference across D1, which lights up blue. O Mine did not do anything. O The potential at the junction between R2 and D1 is pulled low, causing a potential difference across D1, which lights up blue. O The potential at the junction between R2 and D1 is pulled high, causing a potential difference across D2, which lights up yellow O The potential at the junction between R1 and R3 is pulled low, causing a potential difference across D2, which lights up yellow.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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### Understanding Circuit Operation

**Question: What happens when SW2 is closed?**

#### Possible Responses:

1. **Response A:** 
   - Text: "The potential at the junction between R1 and R3 is pulled high, causing a potential difference across D1, which lights up blue."
   - Explanation: This response suggests that when the switch SW2 is closed, the voltage at the junction of resistors R1 and R3 increases. This voltage difference is sufficient to forward bias the diode D1, causing it to emit blue light.

2. **Response B:**
   - Text: "Mine did not do anything."
   - Explanation: This option implies an observed scenario where closing SW2 results in no noticeable change in the circuit. This could be due to various reasons such as an open circuit elsewhere or a faulty component.

3. **Response C:**
   - Text: "The potential at the junction between R2 and D1 is pulled low, causing a potential difference across D1, which lights up blue."
   - Explanation: Here, the closing of SW2 causes the voltage at the junction of resistor R2 and diode D1 to decrease. This creates a potential difference that forward biases D1, illuminating it with blue light.

4. **Response D:**
   - Text: "The potential at the junction between R2 and D1 is pulled high, causing a potential difference across D2, which lights up yellow."
   - Explanation: When SW2 is closed, the voltage at the junction of R2 and D1 rises, creating a potential difference across D2. This causes D2 to forward bias and emit yellow light.

5. **Response E:**
   - Text: "The potential at the junction between R1 and R3 is pulled low, causing a potential difference across D2, which lights up yellow."
   - Explanation: This option suggests that closing SW2 lowers the voltage at the junction of R1 and R3, thus creating a potential difference across D2. This results in D2 being forward biased and lighting up yellow.

#### Analysis:
Understanding the behavior described in each response requires knowledge of how voltages and components interact in circuits. Each option explains a different scenario of potential changes and their influence on diodes and LEDs, emphasizing concepts such as potential difference, forward biasing of diodes, and the resultant emission of light.
Transcribed Image Text:### Understanding Circuit Operation **Question: What happens when SW2 is closed?** #### Possible Responses: 1. **Response A:** - Text: "The potential at the junction between R1 and R3 is pulled high, causing a potential difference across D1, which lights up blue." - Explanation: This response suggests that when the switch SW2 is closed, the voltage at the junction of resistors R1 and R3 increases. This voltage difference is sufficient to forward bias the diode D1, causing it to emit blue light. 2. **Response B:** - Text: "Mine did not do anything." - Explanation: This option implies an observed scenario where closing SW2 results in no noticeable change in the circuit. This could be due to various reasons such as an open circuit elsewhere or a faulty component. 3. **Response C:** - Text: "The potential at the junction between R2 and D1 is pulled low, causing a potential difference across D1, which lights up blue." - Explanation: Here, the closing of SW2 causes the voltage at the junction of resistor R2 and diode D1 to decrease. This creates a potential difference that forward biases D1, illuminating it with blue light. 4. **Response D:** - Text: "The potential at the junction between R2 and D1 is pulled high, causing a potential difference across D2, which lights up yellow." - Explanation: When SW2 is closed, the voltage at the junction of R2 and D1 rises, creating a potential difference across D2. This causes D2 to forward bias and emit yellow light. 5. **Response E:** - Text: "The potential at the junction between R1 and R3 is pulled low, causing a potential difference across D2, which lights up yellow." - Explanation: This option suggests that closing SW2 lowers the voltage at the junction of R1 and R3, thus creating a potential difference across D2. This results in D2 being forward biased and lighting up yellow. #### Analysis: Understanding the behavior described in each response requires knowledge of how voltages and components interact in circuits. Each option explains a different scenario of potential changes and their influence on diodes and LEDs, emphasizing concepts such as potential difference, forward biasing of diodes, and the resultant emission of light.
### Instructions for Experiment

Answer the questions and submit the photos for questions 2-9 using the circuit from STEP 2.

### Circuit Diagram Explanation

The circuit diagram shown is a simple electronic circuit that includes:

- **Power Supply:** A 5V DC power supply (labeled as PSB 5V).
- **Resistors:** Four resistors labeled as 
  - R1 with a value of 50Ω
  - R2 with a value of 50Ω
  - R3 with a value of 100Ω
  - R4 with a value of 100Ω
- **Diodes:** Two light-emitting diodes (LEDs)
  - D1: Blue
  - D2: Yellow
- **Switches:** Two switches
  - SW1
  - SW2

The circuit configuration:

- The power supply (PSB 5V) is connected to both the positive and negative rails of the circuit.
- R1 (50Ω) is connected in series with D2 (Yellow LED).
- R2 (50Ω) is connected to the other side of D2.
- R3 (100Ω) and R4 (100Ω) are in series with each other and connected to D1 (Blue LED).
- SW1 and SW2 are placed in parallel to control the flow of current through the circuit.
- Both LEDs (D1 and D2) along with the resistors have specific placements to ensure the correct flow of current and appropriate dropping of voltage.

When SW1 or SW2 is closed, the circuit completes, allowing current to flow through the appropriate path, lighting up the LEDs (D1 and D2).

### Questions Section

**Question 2:** 

(The specific question text should be inserted here by the educator or the platform providing the lesson material.)

**Question 3:** 

(The specific question text should be inserted here by the educator or the platform providing the lesson material.)

... Continue with questions 4 through 9 ...

This circuit exercise is designed to provide practical experience in working with basic electronic components and understanding series and parallel circuits. Ensure you understand the function of each component and the overall behavior of the circuit before answering the questions and submitting your photos.

### Additional Information

Pay special attention to:
- The color and behavior of the LEDs when switches are opened or closed.
- The resistance and how it affects the current flow and voltage drops.
- The arrangement, noting
Transcribed Image Text:### Instructions for Experiment Answer the questions and submit the photos for questions 2-9 using the circuit from STEP 2. ### Circuit Diagram Explanation The circuit diagram shown is a simple electronic circuit that includes: - **Power Supply:** A 5V DC power supply (labeled as PSB 5V). - **Resistors:** Four resistors labeled as - R1 with a value of 50Ω - R2 with a value of 50Ω - R3 with a value of 100Ω - R4 with a value of 100Ω - **Diodes:** Two light-emitting diodes (LEDs) - D1: Blue - D2: Yellow - **Switches:** Two switches - SW1 - SW2 The circuit configuration: - The power supply (PSB 5V) is connected to both the positive and negative rails of the circuit. - R1 (50Ω) is connected in series with D2 (Yellow LED). - R2 (50Ω) is connected to the other side of D2. - R3 (100Ω) and R4 (100Ω) are in series with each other and connected to D1 (Blue LED). - SW1 and SW2 are placed in parallel to control the flow of current through the circuit. - Both LEDs (D1 and D2) along with the resistors have specific placements to ensure the correct flow of current and appropriate dropping of voltage. When SW1 or SW2 is closed, the circuit completes, allowing current to flow through the appropriate path, lighting up the LEDs (D1 and D2). ### Questions Section **Question 2:** (The specific question text should be inserted here by the educator or the platform providing the lesson material.) **Question 3:** (The specific question text should be inserted here by the educator or the platform providing the lesson material.) ... Continue with questions 4 through 9 ... This circuit exercise is designed to provide practical experience in working with basic electronic components and understanding series and parallel circuits. Ensure you understand the function of each component and the overall behavior of the circuit before answering the questions and submitting your photos. ### Additional Information Pay special attention to: - The color and behavior of the LEDs when switches are opened or closed. - The resistance and how it affects the current flow and voltage drops. - The arrangement, noting
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