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What happens to the resistance of a piece of wire if you double its length and
halve its radius?
Hint: The cross sectional area of a cylindrical wire is A = Tr²
Tr2
The new resistance is 4 times the old resistance.
The new resistance is 1/4 times the old resistance.
The new resistance is 1/8 times the old resistance.
The new resistance is 8 times the old resistance.

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