What happens to the 'mean' of an x-distribution when you standardize the distribution? Z-scores are also known as _______?______ . standard deviations means error ranges
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Z-scores are also known as _______?______ .
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- Using a mean of 10 and standard deviation of 2.45, convert these z-scores back into raw scores. z-score = 1.11 Raw Score= _______________ z-score = -1 Raw Score= ______________ z-score= -0.92 Raw Score= _____________Integrate x2 between -1 and 3 between using both the stone throwing approach and the mean value approach. For m=1 & N=1000, what do you observe if you plot N vs calculated value of the function for both methods? For N=102, 103,104, 105, 106 and m=16 plot the N vs absolute error for both methods. What relationship fits this distribution of points? Comment on what you observe Now plot N against the Standard Deviation (the Variance) for both methods and comment on what you observe.The length of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days. P(x < 245) 11 In the previous question, to determine the fraction of babies born premature, the z-score is ________. a -1.43 b -1.40 c -1.37 d -1.35
- You review your data from a population A and population B. The mean and standard deviation are noted as N(mean, standard deviation). NA(400,10) and NB(300,25). 95 percent of the observations for population A exceed a value of___________?95 percent of the observations for population B are less than a value of _____________?The price (dollars per 1,000 board feet) of Douglas fir from western Washington and Oregon varies according to a triangular distribution T(290, 360, 490). (a) Find the mean. Mean _________ (b) Find the standard deviation. (Round your answer to 2 decimal places.) Standard deviation ____________ (c) What is the probability that the price will exceed 420? (Round your answer to 4 decimal places.) Probability _____________The lengths of pregnancies in a small rural village are normally distributed with a mean of 263 days and a standard deviation of 14 days. A distribution of values is normal with a mean of 263 and a standard deviation of 14.What percentage of pregnancies last fewer than 252 days?P(X < 252 days) = _________%
- Studies show that intelligence test scores or IQ follow a normal distribution (X) with a mean value of 100 and a standard deviation of 15. D) What are Q1, Q2, and Q3 of the distribution of X? Show your work by drawing a normal distribution that includes your answer.Using the square root of x sign above, you will be able to find symbols and equations. Subscripts are also at the top. X2 X2 Now that you have calculated SS. Calculate variance and standard deviation using the same distribution of scores from a population. 3, 7, 8, 5, 6, 4, 9, 10, 7, 8, 6, 5The graph shows the distribution of the number of text Which statement describes the distribution? messages young adults send per day. The distribution is approximately Normal, with a Daily Text Messaging mean of 128 messages and a standard deviation of 98 messages. O The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages. O The distribution is approximately Normal, with a mean of 30 messages and a standard deviation of 128 messages. O The distribution is uniform, with a mean of 128 messages and a standard deviation of 30 messages. 8. 38 68 98 128 158 188 218 248 Number of Texts
- 10 The scores on a test are normally distributed with a mean of 70 and a deviation of 14, What is the score that is 1 1/2 standard deviations below the mean? A score of ______ is 1 1/2 standard deviations below the mean.IQ tests supposedly measure our intelligence. They typically are ‘normed’ so that they have a mean of 100 and a standard deviation of 15. (Higher scores show higher intelligence.) Use the graph and use the z-score and percents from columns b and c in Table A, when relevant. If you scored 132, what is your z-score? (Interpret.) Use table A X, z(a), (b), and (c) X z (a) (b) (c) and use the graph! Write down or save your response to use in Part 2 of this quiz. Group of answer choices -2.53 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. 2.13 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. -2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 0.57 percentile rank and 99.43% of people scored smarter than me. 2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 99.43 percentile rank…Give typing answer with explanation and conclusion Suppose that the duration of trouble-free operation of a new vacuum cleaner is normally distributed with a mean of 550 days and a standard deviation of 100 days. The research department randomly selects 25 customers who bought these vacuum cleaners and records the duration (in days) of trouble-free operation. Which of the following is NOT TRUE for the sample average of number of trouble-free operation days ()? P (x̄ < 500) = P(Z < -2.5) P (x̄ > 600) = P(Z > 2.5) P (x̄ < 520) = P(Z < - 1.5) P (550 < x̄ < 580) = 0.9332