What happens to the force on the rope A-C as the weight changes? O The magnitude stays the same and the angle stays the same. O The magnitude decreases and theta changes. O The magnitude increases and the angle stays the same. The magnitude stays the same and the angle changes.
What happens to the force on the rope A-C as the weight changes? O The magnitude stays the same and the angle stays the same. O The magnitude decreases and theta changes. O The magnitude increases and the angle stays the same. The magnitude stays the same and the angle changes.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:What happens to the force on the rope A-C as the weight changes?
The magnitude stays the same and the angle stays the same.
The magnitude decreases and theta changes.
The magnitude increases and the angle stays the same.
The magnitude stays the same and the angle changes.
![Coplanar forces occur within two dimensions (A plane).
In this activity, you will observe the following when the mass of the crate is changed:
1. The change in the smallest angle theta (8) without either cable failing.
2. The forces on the ropes A-C and A-B.
0
10
C
20
0
30
40
A B
---8
50
+ Fx = 0; -Fc cose + FB = 0;
0 = 0.00⁰
60
70
Fc=
10(10³N) =-
80 90
+1ΣFy = 0;
Fc sine -ON=0
Equation (2)
The maximum force in either rope AB or AC cannot exceed 10 KN without breaking. As seen in the
x-equilibrium equation, Fc is always > FB. Thus, setting Fc to 10 KN represents the load limit of the
ropes.
Substituting Fc = 10 kN into Equation (2), we get
[10 (10³)N] sine -0.00 N = 0
= sin ¹ (0.000) = 0.00⁰
The force developed in rope AB can be obtained by substituting the values for 8 and Fc into Equation (1).
FB
cos
FB
cos 0.00⁰
100 110
FB = 10.00 KN
Drag the slider to change the mass of the crate.
FD
- Equation (1)
120
=
130
F.
B
140 150
0.00 N
X
160
170 180 190 200](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd261088c-f753-45e4-ae14-7adbaf3c257c%2Fc9016a05-21af-452e-9927-0ef0855eba51%2Fgv6aynt_processed.png&w=3840&q=75)
Transcribed Image Text:Coplanar forces occur within two dimensions (A plane).
In this activity, you will observe the following when the mass of the crate is changed:
1. The change in the smallest angle theta (8) without either cable failing.
2. The forces on the ropes A-C and A-B.
0
10
C
20
0
30
40
A B
---8
50
+ Fx = 0; -Fc cose + FB = 0;
0 = 0.00⁰
60
70
Fc=
10(10³N) =-
80 90
+1ΣFy = 0;
Fc sine -ON=0
Equation (2)
The maximum force in either rope AB or AC cannot exceed 10 KN without breaking. As seen in the
x-equilibrium equation, Fc is always > FB. Thus, setting Fc to 10 KN represents the load limit of the
ropes.
Substituting Fc = 10 kN into Equation (2), we get
[10 (10³)N] sine -0.00 N = 0
= sin ¹ (0.000) = 0.00⁰
The force developed in rope AB can be obtained by substituting the values for 8 and Fc into Equation (1).
FB
cos
FB
cos 0.00⁰
100 110
FB = 10.00 KN
Drag the slider to change the mass of the crate.
FD
- Equation (1)
120
=
130
F.
B
140 150
0.00 N
X
160
170 180 190 200
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