What expression needs to go in the box to make this rational equation true? 3x³ + 6x² + 12x A B с D X 2 3x 2x X = x² + 2x + 4

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Question:**

What expression needs to go in the box to make this rational equation true?

\[
\frac{3x^3 + 6x^2 + 12x}{\boxed{}} = x^2 + 2x + 4
\]

**Options:**

- A: \(x^2\)
- B: \(3x\)
- C: \(2x\)
- D: \(x\)

**Explanation:**

To solve this, we must determine which expression, when placed in the box as the divisor, will make the rational equation true. 

This involves checking the expressions by performing polynomial division or simplifying each candidate until the expression on the right side of the equation is achieved.
Transcribed Image Text:**Question:** What expression needs to go in the box to make this rational equation true? \[ \frac{3x^3 + 6x^2 + 12x}{\boxed{}} = x^2 + 2x + 4 \] **Options:** - A: \(x^2\) - B: \(3x\) - C: \(2x\) - D: \(x\) **Explanation:** To solve this, we must determine which expression, when placed in the box as the divisor, will make the rational equation true. This involves checking the expressions by performing polynomial division or simplifying each candidate until the expression on the right side of the equation is achieved.
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