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What does the green vector (whatever color it is on your device - it points from the object toward the center of the circular path) represent and why does it always point toward the center of the circular path? Are there any conditions that would make it change direction? If so, describe those conditions.

What does the green vector (whatever color it is on your device - it points from the object toward the center of the circular path) represent and why does it always point toward the center of the circular path? Are there any conditions that would make it change direction? If so, describe those conditions.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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What does the green vector (whatever color it is on your device - it points from the object toward the center of the circular path) represent and why does it always point toward the center of the circular path? Are there any conditions that would make it change direction? If so, describe those conditions.
This is a simulation of a ball experiencing uniform circular motion, which means it travels in a circle at constant speed. Use the sliders to adjust the speed and the radius of the path. If you show the vectors, you will see the ball’s velocity vector, in blue, and its acceleration vector, in green. The velocity vector is always tangent to the circle, and the acceleration vector always points toward the center of the circle. If the vectors are shown, and the ball has gone about three-quarters of the way around the circle, you will also see a vector triangle. The vector triangle is showing why the ball’s acceleration vector points toward the center. We’re thinking about which way the acceleration vector points at the bottom of the circle. The purple vector shows the velocity just before the ball reaches the bottom point, so we can consider it to be the initial velocity. The light blue vector shows the velocity just after the ball passes through the bottom point, so we can consider it to be the final velocity. The black vector therefore represents the change in velocity at the bottom point - note that the change in velocity points up, which is toward the center of the circle for that lowest point. The acceleration is proportional to the change in velocity (it is the change in velocity divided by the time it takes the ball to move from the purple point to the light blue point), so the acceleration points in the same direction as the change in velocity - toward the center. ### Diagram Explanation The diagram features a circular path with a point representing the ball in motion. The sliders below adjust the speed (currently 2.00 m/s), time (t = 0.00 s), and the radius (1.00 m) of the circle. Simulation written by Andrew Duffy, and first posted on 8-09-2017. This work by Andrew Duffy is licensed under a [Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License](https://creativecommons.org/licenses/by-nc-sa/4.0/). This simulation can be found in the collection at [http://physics.bu.edu/~duffy/classroom.html](http://physics.bu.edu/~duffy/classroom.html). The counter has been running on this page since 8-10-2018. The number of people accessing the page since then is shown at the bottom of the page.
Transcribed Image Text:This is a simulation of a ball experiencing uniform circular motion, which means it travels in a circle at constant speed. Use the sliders to adjust the speed and the radius of the path. If you show the vectors, you will see the ball’s velocity vector, in blue, and its acceleration vector, in green. The velocity vector is always tangent to the circle, and the acceleration vector always points toward the center of the circle. If the vectors are shown, and the ball has gone about three-quarters of the way around the circle, you will also see a vector triangle. The vector triangle is showing why the ball’s acceleration vector points toward the center. We’re thinking about which way the acceleration vector points at the bottom of the circle. The purple vector shows the velocity just before the ball reaches the bottom point, so we can consider it to be the initial velocity. The light blue vector shows the velocity just after the ball passes through the bottom point, so we can consider it to be the final velocity. The black vector therefore represents the change in velocity at the bottom point - note that the change in velocity points up, which is toward the center of the circle for that lowest point. The acceleration is proportional to the change in velocity (it is the change in velocity divided by the time it takes the ball to move from the purple point to the light blue point), so the acceleration points in the same direction as the change in velocity - toward the center. ### Diagram Explanation The diagram features a circular path with a point representing the ball in motion. The sliders below adjust the speed (currently 2.00 m/s), time (t = 0.00 s), and the radius (1.00 m) of the circle. Simulation written by Andrew Duffy, and first posted on 8-09-2017. This work by Andrew Duffy is licensed under a [Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License](https://creativecommons.org/licenses/by-nc-sa/4.0/). This simulation can be found in the collection at [http://physics.bu.edu/~duffy/classroom.html](http://physics.bu.edu/~duffy/classroom.html). The counter has been running on this page since 8-10-2018. The number of people accessing the page since then is shown at the bottom of the page.
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