What do marginal cost, revenue, and profit approximate? If the cost function is C (x) = 4x² + 15, what is the marginal cost? What is C'(10)? Find the exact cost of making the 11th unit and compare that to the marginal cost. Are they close?

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**Understanding Marginal Cost, Revenue, and Profit**

To delve into these fundamental economic concepts, let’s consider the cost function \( C(x) = 4x^2 + 15 \).

1. **Marginal Cost:**
   - Marginal cost represents the cost of producing one more unit of a good. Mathematically, it is the derivative of the cost function, denoted as \( C'(x) \).
   - For the given cost function \( C(x) = 4x^2 + 15 \), the marginal cost function is determined by finding the derivative: 
     \[
     C'(x) = \frac{d}{dx}(4x^2 + 15) = 8x.
     \]
   - The marginal cost when \( x = 10 \) is \( C'(10) = 8(10) = 80 \).

2. **Exact Cost of Making the 11th Unit:**
   - To find the exact cost of producing the 11th unit, calculate the difference \( C(11) - C(10) \):
     \[
     C(11) = 4(11)^2 + 15 = 4(121) + 15 = 484 + 15 = 499,
     \]
     \[
     C(10) = 4(10)^2 + 15 = 4(100) + 15 = 400 + 15 = 415.
     \]
   - The exact cost of making the 11th unit is \( 499 - 415 = 84 \).

3. **Comparison:**
   - Compare the exact cost (84) with the marginal cost (80).
   - These values are quite close, demonstrating how marginal cost provides an approximation of the cost for producing an additional unit, especially useful at large scales.

This exercise illustrates how marginal cost provides an efficient way to approximate changes in total cost with changes in production.
Transcribed Image Text:**Understanding Marginal Cost, Revenue, and Profit** To delve into these fundamental economic concepts, let’s consider the cost function \( C(x) = 4x^2 + 15 \). 1. **Marginal Cost:** - Marginal cost represents the cost of producing one more unit of a good. Mathematically, it is the derivative of the cost function, denoted as \( C'(x) \). - For the given cost function \( C(x) = 4x^2 + 15 \), the marginal cost function is determined by finding the derivative: \[ C'(x) = \frac{d}{dx}(4x^2 + 15) = 8x. \] - The marginal cost when \( x = 10 \) is \( C'(10) = 8(10) = 80 \). 2. **Exact Cost of Making the 11th Unit:** - To find the exact cost of producing the 11th unit, calculate the difference \( C(11) - C(10) \): \[ C(11) = 4(11)^2 + 15 = 4(121) + 15 = 484 + 15 = 499, \] \[ C(10) = 4(10)^2 + 15 = 4(100) + 15 = 400 + 15 = 415. \] - The exact cost of making the 11th unit is \( 499 - 415 = 84 \). 3. **Comparison:** - Compare the exact cost (84) with the marginal cost (80). - These values are quite close, demonstrating how marginal cost provides an approximation of the cost for producing an additional unit, especially useful at large scales. This exercise illustrates how marginal cost provides an efficient way to approximate changes in total cost with changes in production.
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