What different mechanisms can be used to slow the descent of a drop ride? Compare and contrast these options with the Lenz’s law mechanism.
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What different mechanisms can be used to slow the descent of a drop ride? Compare and contrast these options with the Lenz’s law mechanism.
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- A 8.0 kg mass hanging from a spring scale is slowly lowered onto a vertical spring, as shown in (Figure 1). What does the spring scale read just before the mass touches the lower spring? The scale reads 16 NN when the lower spring has been compressed by 1.7 cmcm. What is the value of the spring constant for the lower spring? At what compression length will the scale read zero?The attatched graph is a force over distance graph for a pop-up spring toy. Use the graph to answer the following questions. a. Determine the maximum height the pop-up toy would reach (if it landed perfectly vertical). b. If the spring were to launch the toy horizontally across a felt rug, with a coefficient of kinetic friction μ = 0.35, what would be the velocity of the toy after travelling 0.5 meters beyond its launch point?Please answer question 8 parts a and d
- Please answer it within 30 minutes.I will upvote! Problem: With ball initial velocity of 40m/sCoefficient of kinetic friction between ball and ground is 0.110.How fast is the ball still traveling when it reaches net distance of 18m away?Assume the ball is still in motion on the ground the entire time.Rock Climber Sliding Down a Smooth Slab 9.6 m Hk =0.72 %3D 56° Consider the rock climber climbing on a smooth slab, as shown above: the coefficient of kinetic friction between the climber's rock shoes and the rock is 0.72 the belayer cannot see the climber who is out of sight beyond the edge of the slab the belayer cannot hear the climber because the wind is blowing very hard The climber loses his footing and slides down the slab from rest. How long after the climber loses his footing does the belayer realize she needs to catch the climber's fall? [answer: about 2.1 s] FNET = ma W = mg g = 9.81 m/s? Ax = vot + ½ at?com/course.html?courseld-17255520&OpenVellumHMAC=197f22d4a42226c194d42c759b32e18a#10001 Part A What is the speed of the potato at the lowest point of its motion? A 0.280 kg potato is tied to a string with length 1.50 m, and the other end of the string is tied to a rigid support. The potato is held straight out horizontally from the point of support, with the string pulled taut, and is then released. Express your answer in meters per second. [VD ΑΣΦ 49 a x Xb b √x x x x 1X1 V = m/s Submit Previous Answers Request Answer X Incorrect; Try Again Part B What is the tension in the string at this point? Express your answer in newtons. T = 8.23 N P Pearson Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions Contact 12,772 APR ⠀⠀⠀ 28 A tv A O DII F8 2 M #3 E 80 F3 $ 4 000 000 F4 R % 5 F5 T A 6 F6 Y & 7 ◄◄ F7 U * 00 8 9 DD F9 0 ? X.10n X S ) 0 79 F10 P