whatcapucitur inseries with1002aresistor and20MH willinductuorgivesValuefor theamaxcurrentatfapeavenyof 1000H2?a)1310°F b.) 3.1a1013.3AFd.).3x10-6F

Given:Resistor,r=100ΩInductor,L=20×10-3HFrequency,f=1000HzFind maximum value for the current.Now,The…

Answered: what cupacitur in series with 1002…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

what
capucitur in
series with
1002
a
resistor and
20MH will
inductuor
gives
Value
for the
a
max
current
at
fapeaveny
of 1000H2?
a)1310°F b.) 3.1a10
13.3AF
d.).3x10-6F

Expert Solution

Step 1

$G i v e n : R e s i s t o r, r = 100 Ω I n d u c t o r, L = 20 \times 10^{- 3} H F r e q u e n c y, f = 1000 H z F i n d m a x i m u m v a l u e f o r t h e c u r r e n t . N o w, T h e r e s o n a n c e f r e q u a n c y o f t h e R L C s e r i e s r e s o n a n c e c i r c u i t i s . f_{0} = \frac{1}{2 π} (\sqrt{\frac{1}{L C}}) T a k i n g s q u a r e o n b o t h s i d e s \frac{1}{L C} = 4 π^{2} f_{0}^{2} C = \frac{1}{(4 π^{2} f_{0}^{2}) \times L} = \frac{1}{(4 π^{2} \times {(1000 h Z)}^{2}) \times 20 \times 10^{- 3} H} = 1.212 \times 10^{- 6} F$

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