) What conditions are necessary for your calculations? (Select all that apply.) O uniform distribution of x ✓o is unknown □o is known ✔normal distribution of x ) Find a 90% confidence interval for μ. What is the margin of error? (Round your answers to two d wer limit Oper limit argin of error 0.807 Interpret your results in the context of this problem. obability that this interval contains the true average is 0.80. is a 90% chance that the interval is one of the intervals containing the true average.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Suppose x has a normal distribution with s = 1.7. A random sample of size 12 has a sample mean of x = 50.

### Statistics Problem Explanation

#### Problem Statement
Suppose \( x \) has a normal distribution with \( s = 1.7 \). A random sample of size 12 has a sample mean of \( \bar{x} = 50 \).

#### Part (a): Conditions for Calculations
**Question:** What conditions are necessary for your calculations? (Select all that apply.)

- \(\square\) Uniform distribution of \( x \)
- \(\checked\) \( \sigma \) is unknown
- \(\square\) \( \sigma \) is known
- \(\checked\) Normal distribution of \( x \)

**Explanation:** For the calculations to be valid, we need to assume that the original population \( x \) follows a normal distribution and that the population standard deviation \( \sigma \) is unknown.

#### Part (b): 90% Confidence Interval
**Question:** Find a 90% confidence interval for \( \mu \). What is the margin of error? (Round your answers to two decimal places.)

- Lower limit: [Text box for input]
- Upper limit: [Text box for input]
- Margin of error: **0.807** (This value is given and marked with a red cross, indicating it is incorrect)

**Explanation:** To find the correct 90% confidence interval and margin of error, we typically use the formula 
\[ \text{Margin of Error} = t_{\alpha/2, n-1} \times \frac{s}{\sqrt{n}} \]
where \( t_{\alpha/2, n-1} \) is the t-value from Student’s t-distribution, \( s \) is the sample standard deviation, and \( n \) is the sample size.

#### Part (c): Interpretation
**Question:** Interpret your results in the context of this problem.

- \(\bigcirc\) The probability that this interval contains the true average is 0.80.
- \(\checked\) There is a 90% chance that the interval includes the true average.
- \(\bigcirc\) The probability that this interval contains the true average is 0.20.
- \(\bigcirc\) There is a 20% chance that the interval includes the true average.

**Explanation:** The correct interpretation of a 90% confidence interval is that there is a 90% chance that the computed interval from the sample data includes
Transcribed Image Text:### Statistics Problem Explanation #### Problem Statement Suppose \( x \) has a normal distribution with \( s = 1.7 \). A random sample of size 12 has a sample mean of \( \bar{x} = 50 \). #### Part (a): Conditions for Calculations **Question:** What conditions are necessary for your calculations? (Select all that apply.) - \(\square\) Uniform distribution of \( x \) - \(\checked\) \( \sigma \) is unknown - \(\square\) \( \sigma \) is known - \(\checked\) Normal distribution of \( x \) **Explanation:** For the calculations to be valid, we need to assume that the original population \( x \) follows a normal distribution and that the population standard deviation \( \sigma \) is unknown. #### Part (b): 90% Confidence Interval **Question:** Find a 90% confidence interval for \( \mu \). What is the margin of error? (Round your answers to two decimal places.) - Lower limit: [Text box for input] - Upper limit: [Text box for input] - Margin of error: **0.807** (This value is given and marked with a red cross, indicating it is incorrect) **Explanation:** To find the correct 90% confidence interval and margin of error, we typically use the formula \[ \text{Margin of Error} = t_{\alpha/2, n-1} \times \frac{s}{\sqrt{n}} \] where \( t_{\alpha/2, n-1} \) is the t-value from Student’s t-distribution, \( s \) is the sample standard deviation, and \( n \) is the sample size. #### Part (c): Interpretation **Question:** Interpret your results in the context of this problem. - \(\bigcirc\) The probability that this interval contains the true average is 0.80. - \(\checked\) There is a 90% chance that the interval includes the true average. - \(\bigcirc\) The probability that this interval contains the true average is 0.20. - \(\bigcirc\) There is a 20% chance that the interval includes the true average. **Explanation:** The correct interpretation of a 90% confidence interval is that there is a 90% chance that the computed interval from the sample data includes
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