Homework Help is Here – Start Your Trial Now!
Math
Calculus
What can you conclude? O A. Since f has two different limits along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x,y) approaches (0,0). O B. Since f has the same limit along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0). O C. Since f has the same limit along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x,y) approaches (0,0). O D. Since f has two different limits along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0).

What can you conclude? O A. Since f has two different limits along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x,y) approaches (0,0). O B. Since f has the same limit along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0). O C. Since f has the same limit along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x,y) approaches (0,0). O D. Since f has two different limits along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0).

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
See similar textbooks
icon
Related questions
Question
What can you conclude? O A. Since f has two different limits along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x.y) approaches (0,0). B. Since f has the same limit along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0). C. Since f has the same limit along two different paths to (0,0), it cannot be determined whether or not f has a limit as (X,y) approaches (0,0). D. Since f has two different limits along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0).
Transcribed Image Text:What can you conclude? O A. Since f has two different limits along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x.y) approaches (0,0). B. Since f has the same limit along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0). C. Since f has the same limit along two different paths to (0,0), it cannot be determined whether or not f has a limit as (X,y) approaches (0,0). D. Since f has two different limits along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0).
By considering different paths of approach, show that the function below has no limit as (x,y)→(0,0). x2 + y h(x,y) = y Examine the values of h along curves that end at (0,0). Along which set of curves is ha constant value? O A. y= kx + kx², x# 0, k 0 O B. y= kx°, x+0, k # 0 Ос. У3кx, х#0, k#0 O D. y= kx2, x+ 0, k# 0 If (x,y) approaches (0,0) along the curve when k = 1 used in the set of curves found above, what is the limit? (Simplify your answer.) If (x,y) approaches (0,0) along the curve when k = 2 used in the set of curves found above, what is the limit? (Simplify your answer.)
Transcribed Image Text:By considering different paths of approach, show that the function below has no limit as (x,y)→(0,0). x2 + y h(x,y) = y Examine the values of h along curves that end at (0,0). Along which set of curves is ha constant value? O A. y= kx + kx², x# 0, k 0 O B. y= kx°, x+0, k # 0 Ос. У3кx, х#0, k#0 O D. y= kx2, x+ 0, k# 0 If (x,y) approaches (0,0) along the curve when k = 1 used in the set of curves found above, what is the limit? (Simplify your answer.) If (x,y) approaches (0,0) along the curve when k = 2 used in the set of curves found above, what is the limit? (Simplify your answer.)
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Limits and Continuity
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS