-What can you conclude about the nature of vertical acceleration for a freely falling projectile? b-What do changes in velocity vector components tell us about acceleration? What can you conclude about the nature of the horizontal acceleration of this ball

icon
Related questions
Question

Given the following projectile motion experiment and graphs:

a-What can you conclude about the nature of vertical acceleration for a freely falling projectile?

b-What do changes in velocity vector components tell us about acceleration? What can you conclude about the nature of the horizontal acceleration of this ball

14
1.6
1.2-
y. Object #1
14
1.0
Run #1
Linear
Linear
0.8
1.2
mt + b
mt + b
m = -1.85 ± 0.23
b = 1.63 +0.093
0.6
1.0
m = 1.80 ± 0.10
b = 0.596 ± 0.042
04
0.8-
r= -0,955
x Object #1
r= 0.990
0.2
0.6
Run #1
0.0
04
-0.2
0.0
0.1
0.2
0.3
04
0.5
0.6
0.7
0.0
0.1
0.2
0.3
04
0.5
0.6
0.7
Time (s)
Time (s)
x-pos iton vs time graph
y-pos ition vs time graph
18
16
2-
Linear
vx Object #1
14
mt + b
m = -4.78 + 0.98
b = 349 ± 0.39
-2
12
Run #1
-4
10
Linear
-6
8.
-8
mt + b
r= -0.893
6
-10
m = -7.85 ±1.7
4
-12
b = 1.01 ±0.68
2
vy. Object #1
-14
r= -0.883
-16
-18
Run #1
0.1
0.2
0.2
0.3
04
0.5
0.6
0.1
0.2
0.2
0.3
04
0.5
0.6
Time (s)
Time (s)
vx-position vs time graph
vy-position vs time graph
x-Velocity, Object #1 (m/s)
x-Pos ition, Object #1 (m)
y-Velocity, Object #1 (m/s)
y-Position, Object #1 (m)
Transcribed Image Text:14 1.6 1.2- y. Object #1 14 1.0 Run #1 Linear Linear 0.8 1.2 mt + b mt + b m = -1.85 ± 0.23 b = 1.63 +0.093 0.6 1.0 m = 1.80 ± 0.10 b = 0.596 ± 0.042 04 0.8- r= -0,955 x Object #1 r= 0.990 0.2 0.6 Run #1 0.0 04 -0.2 0.0 0.1 0.2 0.3 04 0.5 0.6 0.7 0.0 0.1 0.2 0.3 04 0.5 0.6 0.7 Time (s) Time (s) x-pos iton vs time graph y-pos ition vs time graph 18 16 2- Linear vx Object #1 14 mt + b m = -4.78 + 0.98 b = 349 ± 0.39 -2 12 Run #1 -4 10 Linear -6 8. -8 mt + b r= -0.893 6 -10 m = -7.85 ±1.7 4 -12 b = 1.01 ±0.68 2 vy. Object #1 -14 r= -0.883 -16 -18 Run #1 0.1 0.2 0.2 0.3 04 0.5 0.6 0.1 0.2 0.2 0.3 04 0.5 0.6 Time (s) Time (s) vx-position vs time graph vy-position vs time graph x-Velocity, Object #1 (m/s) x-Pos ition, Object #1 (m) y-Velocity, Object #1 (m/s) y-Position, Object #1 (m)
1.00 m
Run #1
M Run #1
V Run #1
X Run #1
x Object #1 (m)
y. Object #1 (m)
vx Object #1 (m/ vy. Object #1 (m/
1
0.54
1.24
2
0.54
1.24
1.96
0.17
3
0.81
1.26
2.99
-0.03
4
0.94
1.24
2.06
-0.31
5
1.08
1.22
2.06
-0.72
1.22
1.14
2.00
-1.82
7
1.35
0.98
1.89
-2.86
8
147
0.76
1.89
-3.44
1.60
0.52
0.93
-1.82
10
1.60
0.52
0.07
-3.92
11
1.61
0.00
Transcribed Image Text:1.00 m Run #1 M Run #1 V Run #1 X Run #1 x Object #1 (m) y. Object #1 (m) vx Object #1 (m/ vy. Object #1 (m/ 1 0.54 1.24 2 0.54 1.24 1.96 0.17 3 0.81 1.26 2.99 -0.03 4 0.94 1.24 2.06 -0.31 5 1.08 1.22 2.06 -0.72 1.22 1.14 2.00 -1.82 7 1.35 0.98 1.89 -2.86 8 147 0.76 1.89 -3.44 1.60 0.52 0.93 -1.82 10 1.60 0.52 0.07 -3.92 11 1.61 0.00
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer