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-What can you conclude about the nature of vertical acceleration for a freely falling projectile? b-What do changes in velocity vector components tell us about acceleration? What can you conclude about the nature of the horizontal acceleration of this ball

-What can you conclude about the nature of vertical acceleration for a freely falling projectile? b-What do changes in velocity vector components tell us about acceleration? What can you conclude about the nature of the horizontal acceleration of this ball

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Given the following projectile motion experiment and graphs:

a-What can you conclude about the nature of vertical acceleration for a freely falling projectile?

b-What do changes in velocity vector components tell us about acceleration? What can you conclude about the nature of the horizontal acceleration of this ball

14 1.6 1.2- y. Object #1 14 1.0 Run #1 Linear Linear 0.8 1.2 mt + b mt + b m = -1.85 ± 0.23 b = 1.63 +0.093 0.6 1.0 m = 1.80 ± 0.10 b = 0.596 ± 0.042 04 0.8- r= -0,955 x Object #1 r= 0.990 0.2 0.6 Run #1 0.0 04 -0.2 0.0 0.1 0.2 0.3 04 0.5 0.6 0.7 0.0 0.1 0.2 0.3 04 0.5 0.6 0.7 Time (s) Time (s) x-pos iton vs time graph y-pos ition vs time graph 18 16 2- Linear vx Object #1 14 mt + b m = -4.78 + 0.98 b = 349 ± 0.39 -2 12 Run #1 -4 10 Linear -6 8. -8 mt + b r= -0.893 6 -10 m = -7.85 ±1.7 4 -12 b = 1.01 ±0.68 2 vy. Object #1 -14 r= -0.883 -16 -18 Run #1 0.1 0.2 0.2 0.3 04 0.5 0.6 0.1 0.2 0.2 0.3 04 0.5 0.6 Time (s) Time (s) vx-position vs time graph vy-position vs time graph x-Velocity, Object #1 (m/s) x-Pos ition, Object #1 (m) y-Velocity, Object #1 (m/s) y-Position, Object #1 (m)
Transcribed Image Text:14 1.6 1.2- y. Object #1 14 1.0 Run #1 Linear Linear 0.8 1.2 mt + b mt + b m = -1.85 ± 0.23 b = 1.63 +0.093 0.6 1.0 m = 1.80 ± 0.10 b = 0.596 ± 0.042 04 0.8- r= -0,955 x Object #1 r= 0.990 0.2 0.6 Run #1 0.0 04 -0.2 0.0 0.1 0.2 0.3 04 0.5 0.6 0.7 0.0 0.1 0.2 0.3 04 0.5 0.6 0.7 Time (s) Time (s) x-pos iton vs time graph y-pos ition vs time graph 18 16 2- Linear vx Object #1 14 mt + b m = -4.78 + 0.98 b = 349 ± 0.39 -2 12 Run #1 -4 10 Linear -6 8. -8 mt + b r= -0.893 6 -10 m = -7.85 ±1.7 4 -12 b = 1.01 ±0.68 2 vy. Object #1 -14 r= -0.883 -16 -18 Run #1 0.1 0.2 0.2 0.3 04 0.5 0.6 0.1 0.2 0.2 0.3 04 0.5 0.6 Time (s) Time (s) vx-position vs time graph vy-position vs time graph x-Velocity, Object #1 (m/s) x-Pos ition, Object #1 (m) y-Velocity, Object #1 (m/s) y-Position, Object #1 (m)
1.00 m Run #1 M Run #1 V Run #1 X Run #1 x Object #1 (m) y. Object #1 (m) vx Object #1 (m/ vy. Object #1 (m/ 1 0.54 1.24 2 0.54 1.24 1.96 0.17 3 0.81 1.26 2.99 -0.03 4 0.94 1.24 2.06 -0.31 5 1.08 1.22 2.06 -0.72 1.22 1.14 2.00 -1.82 7 1.35 0.98 1.89 -2.86 8 147 0.76 1.89 -3.44 1.60 0.52 0.93 -1.82 10 1.60 0.52 0.07 -3.92 11 1.61 0.00
Transcribed Image Text:1.00 m Run #1 M Run #1 V Run #1 X Run #1 x Object #1 (m) y. Object #1 (m) vx Object #1 (m/ vy. Object #1 (m/ 1 0.54 1.24 2 0.54 1.24 1.96 0.17 3 0.81 1.26 2.99 -0.03 4 0.94 1.24 2.06 -0.31 5 1.08 1.22 2.06 -0.72 1.22 1.14 2.00 -1.82 7 1.35 0.98 1.89 -2.86 8 147 0.76 1.89 -3.44 1.60 0.52 0.93 -1.82 10 1.60 0.52 0.07 -3.92 11 1.61 0.00
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