What are the wavelengths of electromagnetic wave and sound wave of same frequency 1.9-kHz? Speed of electromagnetic wave is 3x108 m/s, speed of sound wave is 357 m/s.

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### Wavelengths of Electromagnetic and Sound Waves

In this educational module, we will explore the wavelengths of electromagnetic and sound waves that share a common frequency of 1.9 kHz. The speed of the electromagnetic wave is given as \(3 \times 10^8 \, \text{m/s}\), and the speed of the sound wave is \(357 \, \text{m/s}\).

#### Wavelength of Electromagnetic Wave, \(\lambda_1\)
\[ \lambda_1 = \, \_\_\_\_ \]
Units: km (kilometers)

#### Wavelength of Sound Wave, \(\lambda_2\)
\[ \lambda_2 = \, \_\_\_\_ \]
Units: cm (centimeters)

#### Speed of Electromagnetic Wave in a Medium with Dielectric Constant \(\kappa = 2\)
Given the permeability:
\[ \mu = \mu_r \mu_0 = 1.6 \times 10^{-3} \, \text{H/m} \]

Calculate the speed of the electromagnetic wave \(v\) in the medium:
\[ v = \, \_\_\_\_ \]
Units: m/s (meters per second)

### Detailed Instructions:

To solve these problems, you will need to use the following formulas:

1. **Wavelength of Electromagnetic Wave**:
   \[ \lambda_1 = \frac{v_{\text{em}}}{f} \]
   where:
   - \( v_{\text{em}} = 3 \times 10^8 \, \text{m/s} \) (speed of the electromagnetic wave)
   - \( f = 1.9 \times 10^3 \, \text{Hz} \) (frequency)

2. **Wavelength of Sound Wave**:
   \[ \lambda_2 = \frac{v_{\text{sound}}}{f} \]
   where:
   - \( v_{\text{sound}} = 357 \, \text{m/s} \) (speed of the sound wave)
   - \( f = 1.9 \times 10^3 \, \text{Hz} \) (frequency)

3. **Speed of Electromagnetic Wave in the Medium**:
   \[ v = \frac{1}{\sqrt{\kappa \mu_r \mu_0}}
Transcribed Image Text:### Wavelengths of Electromagnetic and Sound Waves In this educational module, we will explore the wavelengths of electromagnetic and sound waves that share a common frequency of 1.9 kHz. The speed of the electromagnetic wave is given as \(3 \times 10^8 \, \text{m/s}\), and the speed of the sound wave is \(357 \, \text{m/s}\). #### Wavelength of Electromagnetic Wave, \(\lambda_1\) \[ \lambda_1 = \, \_\_\_\_ \] Units: km (kilometers) #### Wavelength of Sound Wave, \(\lambda_2\) \[ \lambda_2 = \, \_\_\_\_ \] Units: cm (centimeters) #### Speed of Electromagnetic Wave in a Medium with Dielectric Constant \(\kappa = 2\) Given the permeability: \[ \mu = \mu_r \mu_0 = 1.6 \times 10^{-3} \, \text{H/m} \] Calculate the speed of the electromagnetic wave \(v\) in the medium: \[ v = \, \_\_\_\_ \] Units: m/s (meters per second) ### Detailed Instructions: To solve these problems, you will need to use the following formulas: 1. **Wavelength of Electromagnetic Wave**: \[ \lambda_1 = \frac{v_{\text{em}}}{f} \] where: - \( v_{\text{em}} = 3 \times 10^8 \, \text{m/s} \) (speed of the electromagnetic wave) - \( f = 1.9 \times 10^3 \, \text{Hz} \) (frequency) 2. **Wavelength of Sound Wave**: \[ \lambda_2 = \frac{v_{\text{sound}}}{f} \] where: - \( v_{\text{sound}} = 357 \, \text{m/s} \) (speed of the sound wave) - \( f = 1.9 \times 10^3 \, \text{Hz} \) (frequency) 3. **Speed of Electromagnetic Wave in the Medium**: \[ v = \frac{1}{\sqrt{\kappa \mu_r \mu_0}}
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