What are the largest possible domains for the following functions: (a) f(x,y)= e√x+y (b) f(x, y) = log(x + √log(y)) (c) f(x, y, z)=√√xyz

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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Title: Understanding the Largest Possible Domains for Given Functions**

**Content:**

To find the largest possible domains for the following functions, we need to consider the mathematical operations involved and the constraints they impose.

**(a)** \( f(x, y) = e^{\sqrt{x+y}} \)

- **Explanation:** The function involves an exponential function with an argument of a square root. The expression inside the square root, \( x + y \), must be non-negative for the square root to be defined in the real numbers. Therefore, the domain consists of all pairs \( (x, y) \) such that \( x + y \geq 0 \).

**(b)** \( f(x, y) = \log(x + \sqrt{\log(y)}) \)

- **Explanation:** This function involves a logarithm, which requires its argument to be positive. Therefore, \( x + \sqrt{\log(y)} > 0 \). Additionally, the argument inside the square root, \( \log(y) \), must be non-negative, which means \( y \) must be greater than or equal to 1. Thus, the domain consists of all pairs \( (x, y) \) where \( y \geq 1 \) and \( x + \sqrt{\log(y)} > 0 \).

**(c)** \( f(x, y, z) = \sqrt{xyz} \)

- **Explanation:** The function involves a square root, which requires its argument, \( xyz \), to be non-negative. Therefore, the domain includes all triples \( (x, y, z) \) such that \( xyz \geq 0 \).

These domains ensure that the functions are well-defined in the realm of real numbers. Understanding these constraints helps in determining where each function operates without mathematical errors.
Transcribed Image Text:**Title: Understanding the Largest Possible Domains for Given Functions** **Content:** To find the largest possible domains for the following functions, we need to consider the mathematical operations involved and the constraints they impose. **(a)** \( f(x, y) = e^{\sqrt{x+y}} \) - **Explanation:** The function involves an exponential function with an argument of a square root. The expression inside the square root, \( x + y \), must be non-negative for the square root to be defined in the real numbers. Therefore, the domain consists of all pairs \( (x, y) \) such that \( x + y \geq 0 \). **(b)** \( f(x, y) = \log(x + \sqrt{\log(y)}) \) - **Explanation:** This function involves a logarithm, which requires its argument to be positive. Therefore, \( x + \sqrt{\log(y)} > 0 \). Additionally, the argument inside the square root, \( \log(y) \), must be non-negative, which means \( y \) must be greater than or equal to 1. Thus, the domain consists of all pairs \( (x, y) \) where \( y \geq 1 \) and \( x + \sqrt{\log(y)} > 0 \). **(c)** \( f(x, y, z) = \sqrt{xyz} \) - **Explanation:** The function involves a square root, which requires its argument, \( xyz \), to be non-negative. Therefore, the domain includes all triples \( (x, y, z) \) such that \( xyz \geq 0 \). These domains ensure that the functions are well-defined in the realm of real numbers. Understanding these constraints helps in determining where each function operates without mathematical errors.
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