Question 3 of 14Show AnswerWhat amount of heat, in kJ, wouldbe involved in condensing 10.1 g ofCH;OH? (AHvap = 38.0 kJ/mol)%3DkJ1246.C78+/-x 10 0Tap here or pull up for additional resources3.LO

Given data, Mass of CH3OH=10.1g∆Hvap=38.0kJ/molWe know, Molar mass of CH3OH=32.04g/mol Moles of a substance can be calculated by taking the ratio of given mass is to molar mass, therefore Moles of CH3OH=mass of CH3OHmolar mass of CH3OH=10.1g38.0kJ/mol=0.2658moles∆Hvap=-∆Hcondensation-∆Hcon=Qn , Q=heat, n=number of molesQ=-∆Hvap×n=-38.0kJ/mol×0.2658mol=-10.1kJ

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What amount of heat, in kJ, would be involved in condensing 10.1 g of CH;OH? (AHvap = 38.0 kJ/mol)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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