What actually causes the refraction of a light ray that hits a glass prism at a 45 degree angle to the surface? Compare that refraction to the same situation with a diamond prism. What’s the difference?
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What actually causes the refraction of a light ray that hits a glass prism at a 45 degree angle to the surface?
Compare that refraction to the same situation with a diamond prism. What’s the difference?
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- A ray of light travels with a speed of 2×10^8m/s in a medium X and if its speed is halved in another medium Y .calculate the refractive index of medium X to Y and Y to X?Air has an index of refraction of 1.00. Water has an index of refraction of 1.33. Consider a pool of water that is perfectly calm and 3.21 meters deep. A ray of light (or a laser beam, if you like) enters the water, refracts, and ultimately hits the bottom of the pool. Find the distance between the point where the light enters the water and the point where the light hits the bottom of the pool if the angle between the ray in air and the surface of the pool is 46.4 degrees. Answer in meters.(b). A ray of light passes from glass to water. The angle of incidence in the glass is 35°, take the refractive indices of glass and water to be 1.52 and1.33, respectively. (i). What is the angle of refraction in the water? (ii). At what angle will total internal reflection occur between the glass-water interface?
- A ray of light crosses the boundary between some substance with n = 1.54 and air, going from the substance into air. If the angle of incidence is 29◦ what is the angle of refraction? Calculate to 1decimal.Light is incident at an angle of 52 degrees on the surface of a diamond. The index of refraction of diamond is 2.42. Find the angle of refraction. Answer in units of degrees.The speed of light in crystal is 1.4 x 108 m/s. Calculate the refraction angle when a light ray in air is incident onto the crystal at 36 degrees.(Give your answer in degrees but don't include the units.)
- A point source of light is submerged 2.30 m below the surface of a lake and emits rays in all directions. On the surface of the lake, directly above the source, the area illuminated is a circle. What is the maximum radius that this circle could have?Fiber optic cables, such as those used for high-speed communication (Internet & phone services), transmit signals as light pulses through transparent cables. When viewed from one of the ends, you can see these light pulses, but when viewed from the side you can't. Using your knowledge about reflection and refraction, explain how this might work. Is there some physical limitation where this might not work?