We're trying to find a range of values for the average amour of money that Americans have in a savings account. Would this be an example of point or interval estimation? O Point O Interval
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- For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 980 supermarket shoppers revealed that 264 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.) (b) Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)lower limit upper limit Give a brief explanation of the meaning of the interval. 95% of all confidence intervals would include the true proportion of shoppers who stock up on bargains.5% of all confidence intervals would include the true proportion of shoppers who stock up on bargains. 95% of the confidence intervals created using this method would include the…Scenario: Is there a relationship between test scores (X) and presentation type (Y)? Test scores were quantified using the % correct. Students were able to choose the presentation type of their test — they could take the test online or in-person. Question: What is the scale of measurement for variable X in this scenario? Nominal Ordinal ScaleFor this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 990 supermarket shoppers revealed that 260 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.)________________ (b) Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)lower limit _____________ upper limit _____________
- Let p be the population proportion for the following condition. Find the point estimates for p and g. Of 963 children surveyed, 114 plan to join the armed forces in the future. The point estimate for p, p, is (Round to three decimal places as needed.) P. P. es Help me solve this View an example Get more help- Media . Clear all Check answer Copyright © 2021 Pearson Education Inc. All rights reserved. Terms of UseI Privacy Policy I Permissions Contact Us nere to search 53°F A @ E 99+ 10/05/17The data in the relative frequency bar graph below represents the number of stars earned by 140 performers in a talent competition.How many performers earned exactly 5 stars? Be careful - compare the question wording to the scale on the y-axis of the graph. Notice it says "percentage of performers"Plz answer the question asap
- Medicare spending per patient in different U.S. metropolitan areas may differ. Based on the sample data below, answer the questions that follow to determine whether the average spending in the northern region is significantly less than the average spending in the southern region at the 1 percent level. (a-2) Specify the decision rule. (Use the quick rule to determine degrees of freedom. Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) (b) Find the test statistic tcalc assuming unequal variances. (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.) Medicare Spending per Patient (adjusted for age, sex, and race) Statistic Northern Region Southern Region Sample mean $ 3,978 $ 7,158 Sample standard deviation $ 1,420 $ 3,679 Sample size 13 patients 19 patientsFor this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 994 supermarket shoppers revealed that 272 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.) (b) Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)lower limit upper limit Give a brief explanation of the meaning of the interval. We are 5% confident that the true proportion of shoppers who stock up on bargains falls within this interval.We are 95% confident that the true proportion of shoppers who stock up on bargains falls outside this interval. We are 95% confident that the true proportion of shoppers who…Please explain and answer
- For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 992 supermarket shoppers revealed that 274 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.) (b) Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)lower limit upper limit Give a brief explanation of the meaning of the interval. We are 95% confident that the true proportion of shoppers who stock up on bargains falls within this interval.We are 5% confident that the true proportion of shoppers who stock up on bargains falls above this interval. We are 5% confident that the true proportion of shoppers who…your car is more crowded than you think. table 5.8 reports results from a 1969 personal transportation survey on "home-to-work" trips in metropolitan areas. The survey stated that the average car occupancy was 1.4 people. check that calculation.