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well as 0 and 00 (which are green). If you bet $14 that the outcome is an odd number, the 20 robability of losing the $14 is 38 and the probability of winning $28 (for a net gain of only $1 18 iven you already paid $14) is Complete parts (a) and (b) below. 38

well as 0 and 00 (which are green). If you bet $14 that the outcome is an odd number, the 20 robability of losing the $14 is 38 and the probability of winning $28 (for a net gain of only $1 18 iven you already paid $14) is Complete parts (a) and (b) below. 38

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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I know the first is right but the last one I dont know if its D or B

A roulette wheel has 38 numbers, with 18 odd numbers (black) and 18 even numbers (red), as well as 0 and 00 (which are green). If you bet $14 that the outcome is an odd number, the 20 38 and the probability of winning $28 (for a net gain of only $14, Complete parts (a) and (b) below. probability of losing the $14 is given you already paid $14) is 18 38 a. If a player bets $14 that the outcome is an odd number, what is the player's expected value? The expected value is - 7.37 dollars. (Round to the nearest cent as needed.) b. Is the best option to bet $14 on odd or to not bet? Why? Choose the correct answer below. O A. Betting $14 on odd is best despite having a lower expected value than not betting, betting $14 on odd has a higher possible win than not betting. O B. Not betting is best because it has the highest expected value. O C. Betting on odd is best because it has the highest expected value. D. Not betting is best despite having a lower expected value than betting $14 on odd, because not betting has a lower potential loss.
Transcribed Image Text:A roulette wheel has 38 numbers, with 18 odd numbers (black) and 18 even numbers (red), as well as 0 and 00 (which are green). If you bet $14 that the outcome is an odd number, the 20 38 and the probability of winning $28 (for a net gain of only $14, Complete parts (a) and (b) below. probability of losing the $14 is given you already paid $14) is 18 38 a. If a player bets $14 that the outcome is an odd number, what is the player's expected value? The expected value is - 7.37 dollars. (Round to the nearest cent as needed.) b. Is the best option to bet $14 on odd or to not bet? Why? Choose the correct answer below. O A. Betting $14 on odd is best despite having a lower expected value than not betting, betting $14 on odd has a higher possible win than not betting. O B. Not betting is best because it has the highest expected value. O C. Betting on odd is best because it has the highest expected value. D. Not betting is best despite having a lower expected value than betting $14 on odd, because not betting has a lower potential loss.
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