Welcome X L My Drive x Quiz: Chap x MAT158 Fi X M Stats 2 Fiar X 4 Lumin PDF X O https://ma × b My Questi x + A mail-attachment.googleusercontent.com/attachment/u/0/?ui=2&ik=a1885848c1&attid=D0.1&permmsgid=msg-f:1665506078646919... 9. A store is experimenting to see if having certain scents in the air will influence customer's experience. They randomly try three different scents; lavender, citrus, and vanilla. They then have customers fill out a customer satisfaction survey. From the results, the following ANOVA table is constructed. At the 5% significance level, do the data provide sufficient evidence to conclude that the mean customer satisfaction rating changes depending on the scent used? Source df MS treatment 2 56.58 28.29 6.65 error 14 59.53 4.25 total 16 116.12 2:27 PM O Type here to search 5/1/2020
Welcome X L My Drive x Quiz: Chap x MAT158 Fi X M Stats 2 Fiar X 4 Lumin PDF X O https://ma × b My Questi x + A mail-attachment.googleusercontent.com/attachment/u/0/?ui=2&ik=a1885848c1&attid=D0.1&permmsgid=msg-f:1665506078646919... 9. A store is experimenting to see if having certain scents in the air will influence customer's experience. They randomly try three different scents; lavender, citrus, and vanilla. They then have customers fill out a customer satisfaction survey. From the results, the following ANOVA table is constructed. At the 5% significance level, do the data provide sufficient evidence to conclude that the mean customer satisfaction rating changes depending on the scent used? Source df MS treatment 2 56.58 28.29 6.65 error 14 59.53 4.25 total 16 116.12 2:27 PM O Type here to search 5/1/2020
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Expert Solution
Step 1
Given ANOVA Table
Source | df | SS | MS | F |
Treatment | 2 | 56.58 | 28.29 | 6.65 |
Error | 14 | 59.53 | 4.25 | |
Total | 16 | 116.12 |
Decision Rule
p-value > 0.05, Fail to reject null Hypothesis
p-value < 0.05, Reject null Hypothesis
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