wel (1) Pr( first = black, second = white ) = x3 = 18 = 3 (2) Pr( both are black ) = Pr(1st = black, 2nd = black) = (3) Pr(B and D) = (B,D) total 0.2= 20% = 10 = 5/00 -8 x ²² = 30 = 1/2 8
wel (1) Pr( first = black, second = white ) = x3 = 18 = 3 (2) Pr( both are black ) = Pr(1st = black, 2nd = black) = (3) Pr(B and D) = (B,D) total 0.2= 20% = 10 = 5/00 -8 x ²² = 30 = 1/2 8
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.3: Rules For Addition
Problem 8P
Related questions
Question
I need help I want to know how to get these answers
![ort Answer
(1) Pr( first = black, second = white ) = x3 = 18 = 2
(2) Pr( both are black ) = Pr(1st - black, 2nd = black) = x ² = 30 = 12
72
-
=
(B,D)
2 = 0.2 = 20%
(3) Pr(B and D) =
total
Pr(A and C)
4/10
4
(4) Pr(A given C)
5/10
5
Pr(C)
(5) 8P3 =
=
8!
(8-3)!
8!
5!
8.7.6.5.4.3.2.18x7x6 = 336
5x4×3× 2 × 1
8!
(6) 8C3 =
8.7.6.5.4.3.2.1
8.7.6
336
X
315! (3 × 2 × 1)(5 x 4× 3 × 2 × 1)
3.2.1
= 56
6
06\365(2)
(-)
$65
06 365(2)
(7) P = 100, APR = 6% =.06, n = 365, Y = 2 → A = 100(1+
365
ny
(8) If A = P(1 + APR)", then P = A/ (1 + APR) = 8000 / 2.5 = 3200
(9) b = 6,000,, increase = m = 10% of 6,000 = 600, x = 2 years
y = mx + b = 600(2) + 6,000 = 1,200 + 6,000 = 7,200
t
Q = Qox (1+r)' = 6,000(1+0.10)²
(10) Qo= 6,000, increase = r = 10% = 0.10, 1 = 2 years
-
=
=
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27fb6c92-72fe-4599-a1fe-8d345e48f328%2F648029c2-90b6-4c71-bb00-985643399464%2Fjmjs4hi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ort Answer
(1) Pr( first = black, second = white ) = x3 = 18 = 2
(2) Pr( both are black ) = Pr(1st - black, 2nd = black) = x ² = 30 = 12
72
-
=
(B,D)
2 = 0.2 = 20%
(3) Pr(B and D) =
total
Pr(A and C)
4/10
4
(4) Pr(A given C)
5/10
5
Pr(C)
(5) 8P3 =
=
8!
(8-3)!
8!
5!
8.7.6.5.4.3.2.18x7x6 = 336
5x4×3× 2 × 1
8!
(6) 8C3 =
8.7.6.5.4.3.2.1
8.7.6
336
X
315! (3 × 2 × 1)(5 x 4× 3 × 2 × 1)
3.2.1
= 56
6
06\365(2)
(-)
$65
06 365(2)
(7) P = 100, APR = 6% =.06, n = 365, Y = 2 → A = 100(1+
365
ny
(8) If A = P(1 + APR)", then P = A/ (1 + APR) = 8000 / 2.5 = 3200
(9) b = 6,000,, increase = m = 10% of 6,000 = 600, x = 2 years
y = mx + b = 600(2) + 6,000 = 1,200 + 6,000 = 7,200
t
Q = Qox (1+r)' = 6,000(1+0.10)²
(10) Qo= 6,000, increase = r = 10% = 0.10, 1 = 2 years
-
=
=
X
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