10. Weights of Bears: The health of the bear population in a certain area is monitored byperiodic measurements taken from anesthetized bears. A sample of 54 bears hasweights listed in the bear's data set in the data download. The Minitab worksheet is bearmeasurements.a. Assuming that ơ is known to be 121.8 lb., find a 95% confidence interval estimate ofthe mean of the population of all such bear weights.b. Find a 95% confidence interval estimate of the mean of the population of all suchbear weights, assuming that the population standard deviation ơ is not known.c. Compare the results from parts (a) and (b).11. Body Mass Index: Refer to Body measurements in the data download and usethe sample data. Construct a 95% confidence interval estimate of the standarddeviation of body mass indexes.12. Using Summary Statistics: A study was conducted to estimate hospital costs foraccident victims who wore seat belts. Twenty randomly selected cases have astribution that appears to be bell-shaped with a mean of $9004 and a standarddeviation of $5629 (based on data from the U.S. Department of Transportation).Construct the 95% confidence interval for the mean of all such costs. 7. Mendelian Genetics: When Mendel conducted his famous genetics experiments withpeas, one sample of offspring consisted of 428 green peas and 152 yellow peas.a. Use Minitab to find the following confidence interval estimates of the percentage ofyellow peas.99.5% confidence interval:99% confidence interval:98% confidence interval:95% confidence interval:90% confidence interval:b. After examining the pattern of the above confidence intervals, complete thefollowing statement. “As the degree of confidence decreases, the confidence intervallimitsc. In your own words, explain why the preceding completed statement makes sensethat is, why should the confidence intervals behave as you have described?8. Misleading Survey Responses: In a survey of 1002 people, 701 said that they voted ina recent presidential election (based on data from ICR Research Group). Voting recordsshow that 61% of eligible voters actually did vote. Find a 95% confidence intervalestimate of the proportion of people who say that they voted9. Estimating Car Pollution: In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.06, 0.11,0.16, 0.15, 0.14, 0.08, 0.15 (based on data from the Environmental Protection Agency).Assuming that this sample is representative of the cars in use, construct a 95%confidence interval estimate of the mean amount of nitrogen-oxide emission for all cars.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Answer part c
1. The data in the file represent egg and cheese symbolizes the total fat, in grams per serving, for a sample of 20 egg and cheese sandwiches from a fast food restaurant. The data are as follows: 7 8 3 5 15 21 22 24 18 33 23 31 25 19 29 29 29 30 41 55 1. Find the mean, mode and the median. 2. Construct 95% confidence interval for the population mean total fat, in grams preserving.
Question 1 1. Which IAT data set are you working with? 2. 3. Use StatCrunch and your unique IAT sample to estimate the mean age for the population of IAT participants at the 90% confidence level. Copy the contents of your StatCrunch output window and paste them into your response. (No need to type anything here - just copy and paste the contents of your StatCrunch output window.) Are conditions met to estimate the mean age for the population of IAT participants? (Be sure to support your answer as demonstrated throughout Unit 8.) 4. State the confidence interval, and then interpret the confidence interval in context. 5. What is the margin of error (MOE)? 6. Which would be more accurate, the 90% confidence interval you found or an 85% confidence interval? Briefly explain. Which would be more precise? Briefly explain. One sample T confidence interval: μ: Mean of variable 90% confidence interval results: Variable Sample(IAT-Weight-Score) Sample Mean Std. Err. DF L. Limit U. Limit…
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
2. Assuming that the population is normally distributed, construct a 95% confidence interval estimate for the population mean for each of the following samples: Sample A: 1 1 1 1 8 8 8 8 Sample B: 1 2 3 4 5 6 7 8 Explain why these two samples produce different confidence intervals even though they have the same mean and range.
Question 3 A fruit farmer has a large number of almond trees, all of the same variety and the same age. One year he wishes to estimate the mean yield of his trees. He collects all the almonds from 8 trees and records the following weights (kg); 36 53 78 67 92 77 59 66 a) Use these data to estimate the mean and standard deviation of the yields of all the farmer's trees. b) Construct a 95% confidence interval for the mean yield. c) What statistical assumption is required for your procedure to be valid? d) How might you select a sample of eight trees from those growing in a large field. Criteria [2.1, 2.2, 2.3]
Wk Qu. 13-11 A simulation returns... A simulation returns the following statistics: Mean 100 Standard Deviation: 5 Mode: 96 Minimum:75 Maximum: 135 Standard Error: 8. What is the most likely value? Most likely value A 68% confidence interval for the true mean would start at a value of 92 and end at a value of 108. A 68% confidence interval for the true mean would start at a value of and end at a value 108
ch.8 proportions question4 Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 143 with 65% successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.C.I. =
Chapter 16 covers nonparametric testing procedures. What does nonparametric mean? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a We are not testing population parameters. There is no data involved. The procedure is not based on the assumption of a normal distribution. There are no assumptions that have to be met in order to perform the procedure.
Question 82 parts A, B, and C
Given two dependent random samples with the following results: Population 1 48 29 32 29 38 31 28 Population 2 45 38 41 16 40 28 38 Use this data to find the 95% confidence interval for the true difference between the population means. Assume that both populations are normally distributed. Copy Data Step 2 of 4 : Calculate the sample standard deviation of the paired differences. Round your answer to six decimal places.
Given two dependent random samples with the following results: Population 1 43 32 39 39 44 47 37 Population 2 34 19 36 29 46 35 41 Use this data to find the 90% confidence interval for the true difference between the population means. Let d = (Population 1 entry)-(Population 2 entry). Assume that both populations are normally distributed. Copy Data Step 3 of 4: Find the standard deviation of the paired differences to be used in constructing the confidence interval. Round your answer to one decimal place.

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