Weight of chicken has normal distribution with a mean of 3.6 kg anda variance of 0.16 kg². What percentage of chickens is larger: those thathave weight less than 3.7 kg, or those that have weight between 2.8 and3.8 kg?

Given data: Mean = 3.6 Variance = 0.16

Answered: Weight of chicken has normal…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Natural killer cell activity was measured for subjects in several different groups. Assume that natural killer cell activity follows an approximately normal distribution. Researches want to know if the mean natural killer cell activity levels differ in the population between the groups.
Birth weight at a local hospital for the past year had a normal distribution with a mean of 106 ounces and a variance of 36 ounces2. If the middle 50% of the birth weights are considered to have a normal birth weight then what is the birthweight that defines a high birthweight baby (above normal)?
Two companies produce widgets of varying quality. An important measure of quality is the number of days the widgets can go before they need to be replaced. Do the following data provide evidence that the quality of widgets from the two companies differ? Round the p-value to three decimal places. Do not assume equal variances. Widget Life in Days from Company 1 13.0 13.2 43.2 40.7 55.0 57.3 43.8 49.9 31.7 Widget Life in Days from Company 2 57.1 57.7 59.1 58.7 51.6 57.9
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 5.5 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 24 engines and the mean pressure was 5.7 pounds/square inch with a variance of 0.49. A level of significance of 0.01 will be used. Assume the population distribution is approximately normal. Make the decision to reject or fail to reject the null hypothesis. Dain
The goal of analysis of variance (ANOVA) is toa. detect differences in treatment variances (or variances for different populations).b. detect differences in treatment means (or means for different populations).c. analyze the average variances for different populations.d. analyze the variances of the variances for different populations.
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 5.5 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 24 engines and the mean pressure was 5.7 pounds/square inch with a variance of 0.49. A level of significance of 0.01 will be used. Assume the population distribution is approximately normal. Make the decision to reject or fail to reject the null hypothesis.
Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…
the homogeneity of variances assumption states that the variance in the two samples must be equal? true
Two companies produce small motorcycles of varying quality. An important measure of quality is the top speed the motorcycle can obtain on a flat surface. Do the following data provide evidence that the average top speed of cycles from these two companies differ? Report the p-value to two decimal places. Do not assume equal variances. Top Speed in mph from Company 1 Top Speed in mph from Company 2 21.5 53.0 20.3 40.1 49.6 49.3 43.8 51.6 50.5 52.6 52.5 50.6 47.8 37.0 33.2
Periodically, customers of a financial services company are asked to evaluate the company's financial consultants and services. Higher ratings on the client satisfaction survey indicate better service, with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use a = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating. Assume the population variances are unequal. Consultant A Consultant B n1 = 16 n2 10 X1 = 6,81 X2 = 6.25 %3D S1 = 0.68 S2 = 0.75 (a) State the null and alternative hypotheses. O Hoi H1 - H2 = 0 Hai H1- Hz>0 O Ho: H1 - 42 = 0 Hại H1 - H2# 0 O Ho: H1 - H2 > 0 %3D Ha: H1 - H2 = 0 O Ho: H1 - Hz # 0 Hai Hy - Hz = 0 Hoi H1 - H2 = Hai H1- H2 = 0 (b) Compute the value of the test statistic. (Round your answer to three decimal places.) 19.191 (c) What is the p-value?…
Low-density lipoprotein, or LDL, is the main source of cholesterol buildup and blockage in the arteries. This is why LDL is known as "bad cholesterol." LDL is measured in milligrams per deciliter of blood, or mg/dL. In a population of adults at risk for cardiovascular problems, the distribution of LDL levels is normal, with a mean of 123 mg/dL and a standard deviation of 41 mg/dL. If an individual's LDL is at least 1 standard deviation or more above the mean, he or she will be monitored carefully by a doctor. What percentage of individuals from this population will have LDL levels 1 or more standard deviations above the mean? Use the 68–95–99.7 rule. (Enter your exact answer as a whole number.) percentage %

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS

Weight of chicken has normal distribution with a mean of 3.6 kg and a variance of 0.16 kg². What percentage of chickens is larger: those that have weight less than 3.7 kg, or those that have weight between 2.8 and 3.8 kg?