Wedge fringes are formed in the air gap between two glass slides of length 19.9 cm, separated at one end by a 10.0 micron (10.0x106) piece of paper. The wedge is illuminated by monochromatic light of wavelength 528 nm. Calculate the distance between adjacent dark fringes, giving your answer in m to 4d.p.
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- Light of wavelength 430 nm in water illuminates a glass (n = 1.5) wedge submerged in water (n = 1.33). If the distance between successive bright fringes is 6 mm... Find the change in thickness of the glass between these fringes: 215 nm; And the angle of the wedge radians.The walls of a soap bubble have about the same index of refraction as that of plain water, n = 1.33. There is air both inside and outside the bubble. What wavelength (in air) of visible light is most strongly reflected from a point on a soap bubble where its wall is 340. nm thick? Note: Your answer is assumed to be reduced to the highest power possible.A Fresnel biprism placed midway between a point source and a screenis used to obtain fringes from the source placed 2 m from the screen. If the wavelength of light isλ0 = 500 nm and the refractive index of the glass is n=1.5, what is the angle of the prism if the separation between fringes is 0.5 mm?
- A particular person's pupil is 4.5 mm in diameter, and the person's normal‑sighted eye is most sensitive at a wavelength of 552 nm. What is angular resolution ?R of the person's eye, in radians?A single slit of width 4.50 x 10 ºm produces a first-order dark fringe at some angle. If the width of the slit is now changed to 3.08 × 10-ºm, a second-order dark fringe is found at three times the previous angle. What is the wavelength of the light?A single slit with a slit width of 0.48 mm is illuminated with monochromatic light having a wavelength of 491 nm. At what distance away should a screen be placed so that the central maxima has a spatial width of .52 cm. Express the distance in meters.