We wrap a light, nonstretching cable around a solid cylinder of mass 5.0 kg and diameter of 0.120 m, which rotates with frictionless bearings, as shown in the Figure. We pull the free end of the cable with a constant 9.0 N force. What is the cable's acceleration? 90N 50 kg 0.120 m to the cylinder's surface, sei lever am is the raF-90N R=0.060m Mg The weight and normal force both act on a line through the axis of rotation. so they exert no loque -x û Countercloc

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We wrap a light, nonstretching cable around a solid cylinder of mass 5.0 kg and diameter of
0.120 m, which rotates with frictionless bearings, as shown in the Figure. We pull the free
end of the cable with a constant 9.0 N force. What is the cable's acceleration?
(a)
90N
50 kg
0.120 m
(b) Facts tangent to the cylinder's
surface, so its lever arm
is the radi.
F=9.0 N
R=0,060m
Mg
The weight and
normal force both
act on a line through
the axis of rotation,
so they exert no
Lonque.
-X
Counterclose
tonques are poutive.
Transcribed Image Text:We wrap a light, nonstretching cable around a solid cylinder of mass 5.0 kg and diameter of 0.120 m, which rotates with frictionless bearings, as shown in the Figure. We pull the free end of the cable with a constant 9.0 N force. What is the cable's acceleration? (a) 90N 50 kg 0.120 m (b) Facts tangent to the cylinder's surface, so its lever arm is the radi. F=9.0 N R=0,060m Mg The weight and normal force both act on a line through the axis of rotation, so they exert no Lonque. -X Counterclose tonques are poutive.
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