We would like to investigate whether there is a relationship between weather conditions and the inci dence of violent crime. We classified 1361 homocides according to the season, resulting in the following data: Winter Spring Summer 340 395 358 268 Test the null hypothesis of equal proportions using a significance level of a = 0.01.
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- To determine if there is an association between gender and reading habits, 270 adults are randomly sampled from across the United States and asked the following question: “How often do you read a book outside of work or school: regularly, sometimes, or never?” The results are summarized in the following table: OBSERVED READING HABITS Regularly Sometimes Never Total Male 42 72 10 124 Female 72 74 7 146 Total 107 146 17 270 A)Suppose the chi-square test statistic is 3.7329254 with 2 degrees of freedom. Using the chi-square table, what is the p-value for this test? B)Suppose the p-value is 0.11. At the a = 0.05 level, what conclusion should be made?Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.In a random sample of 925 plain M&M's, 19% were blue. Use a 0.01 significance level to test the claim of Mars, Inc. that 24% of its plain M&M candies are blue. a. Define the parameter A. p = The proportion of all M&M's that are blue B. mu = The proportion of all M&M's that are blue C. mu = The mean number of all M&M's that are blue D. p = The proportion of all M&M's that are not blue b. State the null and alternative hypotheses A. Upper H 0 : p greater than 0.24 Upper H 1 : p equals 0.24 B. Upper H 0 : p equals 0.19 Upper H 1 : p not equals 0.19 C. Upper H 0 : p equals 0.24 Upper H 1 : p not equals 0.24 D. Upper H 0 : mu not equals 0.24 Upper H 1 : mu equals 0.24 c. Calculate the test statistic. Which of these options is closest to the test statistic? A. negative 4.00 B. negative 3.65 C.…
- A police department released the numbers of calls for the different days of the week during the month of October, as shown in the table to the right. Use a 0.01 significance level to test the claim that the different days of the week have the same frequencies of police calls. What is the fundamental error with this analysis? a. Calculate the test statistic, chi squared .chi squared equals (Round to three decimal places as needed.) b. Calculate the P-value. P-valueequals (Round to four decimal places as needed.)Find the range, variance, and standard deviation for the given sample data, if possible. If the measures of variation can be obtained for these values, do the results make sense? Biologists conducted experiments to determine whether a deficiency of carbon dioxide in the soil affects the phenotypes of peas. Listed below are the phenotype codes, where 1 equals smooth-yellow, 2 equals smooth-green, 3 equals wrinkled yellow, and 4 equals wrinkled-green. a. The range of the sample data is (Type an integer or a decimal. Do not round.) b. the standard deviation of the sample data is (Round to one decimal place as needed.) c. The variance of the sample data is (Round to one decimal place as needed.)Consider the following 3 independent sample statistics (from Exercise 11.2.1, pg 454): Sample 1: Mean=43, SD=3.74, n=4, Sample 2: Mean=44, SD=4, n=3, Sample 3: Mean=34, SD=3.92, n=4. Compute the SS(between) and the SS(within). Type the three digit numbers, first representing the SS(between) and second the SS(within), separated by comma with no spaces; e.g., 350,278 SHOW THE STEPS I NEED A NEW ANSWER PLEASE
- Listed below are the lead concentrations (in ug/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 µg /g. 2.96 6.45 5.99 5.51 20.53 7.45 11.97 20.46 11.52 17.54 D Identify the null and alternative hypotheses. Ho: H1: (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. V the null hypothesis. There sufficient evidence at the 0.01 significance level to V the claim that the mean lead concentration for all Ayurveda medicines…To determine if there is an association between gender and reading habits, 270 adults are randomly sampled from across the United States and asked the following question: “How often do you read a book outside of work or school: regularly, sometimes, or never?” The results are summarized in the following table: OBSERVED READING HABITS Regularly Sometimes Never Total Male 42 72 10 124 Female 72 74 7 146 Total 107 146 17 270 a)What are the appropriate hypotheses for this chi-square test? b)What are the appropriate degrees of freedom for this test?The average family size was reported as 7.2. A random sample of families in a particular school district resulted in the following family sizes: Size 4 9. 8. 4 8 9 At 1% level of significance, does the average family size different from the national average? Use traditional way of testing hypothesis. a. Mean family size of the sample: b. Sample variance: ct Test Value: d. Summarize your Interpretation: 4)
- Monthly salary computations from two different clothing companies yielded the following data: n=7, ?=9,130$, ?=386$; ?= ?, ?=8,840$, ?=212$. At the level of significance 0.05, can we conclude that the mean monthly salary from the two companie is not the same?Listed below are the number of cricket chirps in 1 min and the corresponding temperatures in degrees Fahrenheit. Is there sufficient evidence to conclude that there is a relationship between the number of cricket chirps in 1 min and the temperature? Use a significance level of α=0.05. Chirps in 1 min 1171 1105 1185 852 1089 950 917 862 Temperature (°F) 78.4 88.2 91.5 86.3 90.2 79.3 83.8 84.4 Determine the null and alternative hypotheses for this test. Find the value of the correlation coefficient. rs=enter your response here (Round to three decimal places as needed.) Determine the critical value(s) of the correlation coefficient. enter your response here (Round to three decimal places as needed. Use a comma to separate answers as needed.)Listed below are the number of cricket chirps in 1 min and the corresponding temperatures in degrees Fahrenheit. Is there sufficient evidence to conclude that there is a relationship between the number of cricket chirps in 1 min and the temperature? Use a significance level of α=0.05. Chirps in 1 min 1073 977 1186 888 994 1087 970 952 Temperature (F) 75.4 83.6 73.2 69.3 72.7 74.9 90.8 88.7 1. Determine the null and alternative hypotheses for this test. 2. Find the value of the correlation coefficient. 3. Determine the critical value(s) of the correlation coefficient.