We wish to test the null hypothesis that the proportion of cancer deaths among people exposed to radioactive fallout in Utah in 1955 is equal to 0.15 versus the alternative hypothesis that the proportion differs from 0.15 using alpha = 0.05.What is the region of rejection for this test for a sample of size 20?Reject H₀ if y in { LIST y VALUES HERE }

Null hypothesisH0 : p = 0.15H1 : p ≠ 0.15α=0.05

Answered: We wish to test the null hypothesis…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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9. What is the number of degrees of freedom for the standardized test statistic in the comparison population means using two small, independent samples of sizes 16 and 22 given sample standard deviations of 3.2 and 2.5 respectively? df = 11. A hypothesis test is conducted with H0 : µ1 - µ2 = 4 vs. Ha: µ1 - µ2 > 4 . Given the sample data below, what is the observed tail area, P, of the test given? n1= 42, x1= 52.8, s1= 6.0, n2= 59, x2= 44.7, s2= 8.4 C. 0.0043 A. 0.0034 B. 0.0021 D. 0.0068
Women are recommended to consume 1790 calories per day. You suspect that the average calorie intake is larger for women at your college. The data for the 11 women who participated in the study is shown below: 2035, 2079, 1842, 1923, 1701, 1889, 1691, 1731, 1730, 2006, 1954 Assuming that the distribution is normal, what can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer = > < ≠ H1:H1: ? μ p Select an answer ≠ < = > The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean calorie…
2. DETAILS ASWSBE15 13.E.002.MI. You may need to use the appropriate technology to answer this question. In a completely randomized design, eight experimental units were used for each of the five levels of the factor. Complete the following ANOVA table. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum of Variation of Squares Treatments Error Total Submit Answer 300 460 Degrees of Freedom Mean Square p-value
Suppose you want to test the claim that u, > H,. Two samples are randomly selected from normal populations. The sample statistics are given below. Assume that o #o5. At a level of significance of a = 0.01, when should you reject Ho? n, = 18, n2 =13, x, = 470, x2 = 455, s, = 40, s2 = 25 %3D O A. Reject H, if the standardized test statistic is greater than 2.681. B. Reject Ho if the standardized test statistic is greater than 1.699. O C. Reject H, if the standardized test statistic is greater than 3.055. D. Reject H, if the standardized test statistic is greater than 2.179.
32.
For a fixed alpha level of significance used for a hypothesis test, the critical value for a chi-square statistic decreases as the size of the sample decreases. a. True b. False
We want to use a z-test to determine if the sample mean is greater than 20 at the alpha = 0.05. What is the critical value(s)?
My answer is as follows: T critical = 2.70 T value= 7.775 P< a (0.01) Therefore we reject the null. Is this correct?
What is the cut off score on a Chi-Square distribution in a Goodness of Fit Chi Square Test when the variable has 6 categories and a sample size of 20? Assume a significance level=.05. a. 5 b. 12.59 c. 6 d. 11.0
If you collect data from a random sample of 10 students and we would like test for statistical significance at the 0.05 level, what critical r value must be obtained? O .602 O.632 0.708 O .576
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120
An adviser in student services would like to estimate the average monthly car payment of all IRSC students. From past research, it is known that the standard deviation of the distribution of all IRSC student car payments is $49. Determine the sample size necessary such that the margin of error of the estimate for a 96% confidence interval for the average monthly car payment of all IRSC students is at most $4.74. Round the solution up to the nearest whole number. n=

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