We wish to estimate what percent of adult residents in a certain county are parents. Out of 300 adult residents sampled, 240 had kids. Based on this, construct a 95% confidence interval for the proportion p of adult residents who are parents in this county. Express your answer in tri-inequality form. Give your answers as decimals, to three places.  < p <  Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places. p =  ±

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: The objective of this question is to construct a 95% confidence interval for the proportion of adult…

Q: Explain how the Choosing of a Level of Confidence is done.

A: The level of confidence represents how often the true percentage of the population lies within the…

Q: í 600 people sampled, 348 had kids.

A: Given that  Sample size (n) = 600 Had kids (X) = 348   We know that  Best point estimate (p)= xn…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 300…

A: Critical Value: In test of hypotheses, Critical Values are the cut-off values that provide with the…

Q: A national polling organization surveyed 1000 Americans and found that 350 admitted to being guilty…

A: Given: x=350 n=1000 p^=xn=3501000=0.35

Q: We wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 500…

A: The sample proportion of the sample of size n can be defined as:  Here, X = Total number of success…

Q: he confidence interval was (73, 83) What was the point estimate? What was the margin of error?

A: Given: Lower limit =73 Upper limit =83 The point estimate can be calculated as: Point estimate…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 300…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 300…

A: It is given that sample size (n) is 300 and x is 15.

Q: The confidence interval for a population porportion is (0.34, 0.5). What the the sample proportion…

A: Given  The confidence interval for a population proportion (0.34,0.5)  estimate the sample…

Q: According to a recent survey of 1479 voters, 39% feel that the president is doing an acceptable job.…

A: A recent survey of 1479 voters are taken of which 39% feel the president is doing an acceptable job.…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: Solution: It is given here:

Q: e confidence interval for a population mean is (240.53, 240.79). What are the sample mean and the…

A: The confidence interval for a population mean is (240.53, 240.79)WE HAVE TO FIND OUT THE MEAN AND…

Q: The FDA claims that the mean nicotine content exceeds 31.0 milligrams for this brand of cigarette,…

A: It is given that that the confidence interval at a 90% level of significance is (26.79, 30.10). And…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 300…

A: Given data,n=300x=75p=xn=75300=0.25z-value at 95% confidence is Zc=1.96

Q: What type of educational background do CEOs have? In one survey, 344 CEOs of medium and large…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A: Given X=25 n=500 95% confidence interval

Q: A poll of 1785 U.S. adults found that 900 U.S. adults, or 50.42% regularly used Facebook as a news…

A: Given that: Sample proportion, p^=0.5042 sample size (n) =900

Q: In a survey of 323 adults over 50, 60% said they were taking vitamin supplements. Find the margin of…

A:

Q: x=111, n=194, Confidence level = 99%

A: The sample proportion of p is, p^=xn=111194=0.5722 Computation of critical value:…

Q: In a study conducted to estimate the true proportion of people that have been to a music festival,…

A: A sample of 114 out of 385 people randomly sampled have been to the music festival.

Q: BCD Travel wants to estimate the population proportion of adults who favor historical sites for…

A: p^ = 59% = 0.59Sample size = 24086% confidence level

Q: An epidemiologist wants to estimate the proportion of residents in her city that carry the Hepatatis…

A:

Q: lculating the confidence interval.

A: x Freq 1 3 2 5 3 19 4 7 5 6 Total 40

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: The sample size is 1072, 67% say they are willing to get a second or part-time job to pay for their…

Q: The confidence interval for a population porportion is (0.57, 0.73). What the the sample proportion…

A: Given the confidence interval for a population porportion is (0.57, 0.73).That is, lower confidence…

Q: Convert the estimate and your confidence interval to Percents. Discuss reasons the estimate might be…

A: We have to convert the estimate and confidence interval into the percentage.

Q: lution is incorrect since the  confidence level is 90% margin of error is 3%

A: Given: Confidence level = 0.90 Margin of error (E) = 0.03 Assumed sample proportion  p^     = 0.50

Q: For a confidence level of 99% with a sample size of 22, find the t-score. Did not see how to work…

A: The provided information is:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: Solution a)  0.156&lt;p&lt;0.324 b)  p=0.240±0.084

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Number of adult residents (n) = 600 Number of adults that has kids (x) = 102 Find z-critical value:…

Q: Use the confidence interval to find the margin of error and the sample mean. (1.59,1.89)

A: Given data,Lower limit=1.59Upper limit=1.89Margin of error=?