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We wish to analyze the circuit of Fig. 6.24(a) to determine the voltages at all nodes and the currents through all branches. Note that this circuit is identical to that of Fig. 6.23 except that the voltage at the base is now -6 V. Assume that the transistor ß is specified to be at least 50. +6 V +10 V www 4.7 ΚΩ 3.3 ΚΩ 10 - 5.5 4.7 5.3 3.3 31.6 mA +6 V +6 V -0.96 mA +10 V (5) 0.64 mA 1.6 mA 3.3 ΚΩ +10 V 4.7 k 4.7 kn - 10-1.6 x 4.7-2484 Impossible, not in active mode -06-0.7 +5.3 V (1) 5.3 3.3 = 1.6 mA (2) (b) -O 5.3 + 0.2= +5.5 V (3) 06-0.7 = +5.3 V1 3.3 ΚΩ Figure 6.24 Analysis of the circuit for Example 6.5. Note that the circled numbers indicate the order of the analysis steps.

We wish to analyze the circuit of Fig. 6.24(a) to determine the voltages at all nodes and the currents through all branches. Note that this circuit is identical to that of Fig. 6.23 except that the voltage at the base is now -6 V. Assume that the transistor ß is specified to be at least 50. +6 V +10 V www 4.7 ΚΩ 3.3 ΚΩ 10 - 5.5 4.7 5.3 3.3 31.6 mA +6 V +6 V -0.96 mA +10 V (5) 0.64 mA 1.6 mA 3.3 ΚΩ +10 V 4.7 k 4.7 kn - 10-1.6 x 4.7-2484 Impossible, not in active mode -06-0.7 +5.3 V (1) 5.3 3.3 = 1.6 mA (2) (b) -O 5.3 + 0.2= +5.5 V (3) 06-0.7 = +5.3 V1 3.3 ΚΩ Figure 6.24 Analysis of the circuit for Example 6.5. Note that the circled numbers indicate the order of the analysis steps.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can someone explain this problem step by step? How do I know is in active more, or saturation mode? If you know those conditions , how do we suppose to work it out. Also why step 2 and 3 the current are almost the same
Example 6.5 We wish to analyze the circuit of Fig. 6.24(a) to determine the voltages at all nodes and the currents through all branches. Note that this circuit is identical to that of Fig. 6.23 except that the voltage at the base is now -6 V. Assume that the transistor ß is specified to be at least 50. +6 V +10 V (a) 4.7 k • 3.3 ΚΩ 10 - 5.5 4.7 5.3 3.3 31.6 mA MA +6 V +6 V = 0.96 mA +10 V (5) 0.64 mA = 1.6 mA 3.3 ΚΩ + 10 V 4.7 ΚΩ 4.7 ΚΩ 5.3 3.3 10-1.6 x 4.724 Impossible, not in active mode -06-0.7 +5.3 V (1) 6.3 BJT Circuits at DC 337 = 1.6 mA (2) (b) 5.3 + 0.2= +5.5 V (3) -06-0.7 +5.3 V 3.3 ΚΩ Figure 6.24 Analysis of the circuit for Example 6.5. Note that the circled numbers indicate the order of the analysis steps.
Transcribed Image Text:Example 6.5 We wish to analyze the circuit of Fig. 6.24(a) to determine the voltages at all nodes and the currents through all branches. Note that this circuit is identical to that of Fig. 6.23 except that the voltage at the base is now -6 V. Assume that the transistor ß is specified to be at least 50. +6 V +10 V (a) 4.7 k • 3.3 ΚΩ 10 - 5.5 4.7 5.3 3.3 31.6 mA MA +6 V +6 V = 0.96 mA +10 V (5) 0.64 mA = 1.6 mA 3.3 ΚΩ + 10 V 4.7 ΚΩ 4.7 ΚΩ 5.3 3.3 10-1.6 x 4.724 Impossible, not in active mode -06-0.7 +5.3 V (1) 6.3 BJT Circuits at DC 337 = 1.6 mA (2) (b) 5.3 + 0.2= +5.5 V (3) -06-0.7 +5.3 V 3.3 ΚΩ Figure 6.24 Analysis of the circuit for Example 6.5. Note that the circled numbers indicate the order of the analysis steps.
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