We want to use Newton's Method to approximate V101. We can do this by letting f(x) = a4 f(x) = a4 101. For the function - 101, write Newton's formula as f(xn) Xn+1 F(xn) = Xn for solving - f(x) = 0. Type in x_n for xn Xn +1 Now use this to approximate the value of V101 (accurate to 6 decimals. 101 2

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