We want to fit v = k1 * exp(-k2 * u) to the data: (0, 1.95), (1, 1.28), (2, 0.70) by least-squares fitting of a straight line to: Ln(v) = c1 + c2 (-u). The matrix b = FT *y is 0.558 0.467 0.558 0.467 3.93 2.68 O[ 0.558 2.680

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