We want to find functions u₁(x) and u₂(x) such that yp = U₁Y₁+U₂Y₂ is a particular solution. We can find the derivatives of these functions as follows. W U₁ = = -e-2x(2 + ex)-1 -e-3x W₂ e-x(2 + ex)-1 -e-3x
We want to find functions u₁(x) and u₂(x) such that yp = U₁Y₁+U₂Y₂ is a particular solution. We can find the derivatives of these functions as follows. W U₁ = = -e-2x(2 + ex)-1 -e-3x W₂ e-x(2 + ex)-1 -e-3x
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
Related questions
Question
![We have found the following Wronskians.
W = -e-³x; W₁ = -
We want to find functions u₁(x) and u₂(x) such that yp = U₁Y₁ + U₂y₂ is a particular solution. We can find the derivatives of these functions as follows.
W
=
1
W
-e-2x(2 + ex)-1
-e-3x
-e-²x(2 + ex)-¹; W₂ = e¯x(2 + ex)-¹
W₂
W
ex(2 + ex)-1
-e-3x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67422373-dd59-4911-9953-d708f15d2285%2Fa7597896-846e-4ac7-a5da-f5d22e959a50%2Fmxo1639_processed.png&w=3840&q=75)
Transcribed Image Text:We have found the following Wronskians.
W = -e-³x; W₁ = -
We want to find functions u₁(x) and u₂(x) such that yp = U₁Y₁ + U₂y₂ is a particular solution. We can find the derivatives of these functions as follows.
W
=
1
W
-e-2x(2 + ex)-1
-e-3x
-e-²x(2 + ex)-¹; W₂ = e¯x(2 + ex)-¹
W₂
W
ex(2 + ex)-1
-e-3x
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Follow-up Questions
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Follow-up Question
![We have found the following complementary function for the given differential equation.
Y=₁₂x+
c₂e-2x
We have also found that for y₁ = ex, y₂ = e-²x, ‚ U₁ = In(2 + e*), and U₂ = 2 In(2 + e*) – e*, a particular solution for the equation is given by y₁ = U₁Y₁+U₂Y₂
To finish, use the fact that y = y + y is the general solution of the nonhomogeneous differential equation to solve.
y(x) =](https://content.bartleby.com/qna-images/question/67422373-dd59-4911-9953-d708f15d2285/87ff4951-567c-4b15-b66f-5a8965da11f2/0rv7t2_thumbnail.png)
Transcribed Image Text:We have found the following complementary function for the given differential equation.
Y=₁₂x+
c₂e-2x
We have also found that for y₁ = ex, y₂ = e-²x, ‚ U₁ = In(2 + e*), and U₂ = 2 In(2 + e*) – e*, a particular solution for the equation is given by y₁ = U₁Y₁+U₂Y₂
To finish, use the fact that y = y + y is the general solution of the nonhomogeneous differential equation to solve.
y(x) =
Solution
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